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Microprocessor and Microcontroller (4341101) - Summer 2023 Solution

23 mins· ·
Study-Material Solutions Microprocessor 4341101 2023 Summer
Milav Dabgar
Author
Milav Dabgar
Experienced lecturer in the electrical and electronic manufacturing industry. Skilled in Embedded Systems, Image Processing, Data Science, MATLAB, Python, STM32. Strong education professional with a Master’s degree in Communication Systems Engineering from L.D. College of Engineering - Ahmedabad.
Table of Contents

Question 1(a) [3 marks]
#

Compare Microprocessor and Microcontroller.

Answer:

FeatureMicroprocessorMicrocontroller
DefinitionCPU on single chipComplete computer on single chip
MemoryExternal RAM/ROM neededBuilt-in RAM/ROM
ApplicationsGeneral computing, PCsEmbedded systems, IoT
ExamplesIntel 8085, 80868051, Arduino, PIC
CostHigherLower

Mnemonic: “PCRAM” - “Processors Connect to RAM, Microcontrollers Already have Memory”

Question 1(b) [4 marks]
#

Compare RISC and CISC.

Answer:

FeatureRISC (Reduced Instruction Set Computer)CISC (Complex Instruction Set Computer)
InstructionsFew, simple instructionsMany, complex instructions
Execution TimeFixed (1 clock cycle)Variable (multiple cycles)
Memory AccessOnly through load/storeMultiple memory access modes
PipeliningEasy implementationDifficult implementation
ExamplesARM, MIPSIntel x86, 8085
HardwareSimple, less transistorsComplex, more transistors
Register SetLarge number of registersFewer registers

Mnemonic: “RISC-Fast, CISC-Many” (RISC uses Fast execution, CISC has Many instructions)

Question 1(c) [7 marks]
#

Define: Microprocessor, Operand, Instruction Cycle, Opcode, ALU, Machine Cycle, T-State

Answer:

TermDefinition
MicroprocessorCPU on a single integrated circuit that processes instructions
OperandData value used in an instruction operation
Instruction CycleComplete process to fetch, decode and execute an instruction
OpcodeOperation code that tells CPU what operation to perform
ALUArithmetic Logic Unit that performs mathematical computations
Machine CycleBasic operation like memory read/write (subset of instruction cycle)
T-StateTime state - smallest unit of time in processor operation (clock period)

Diagram:

FGfEerTtoCmHinmsetmrourcytionINSTDIIREndUCteCOenTDrtIEpiOrfNeytCoYopCpeLcrEoadnedsEPSXetEroCfrUoeTrEmreospuelrtastion

Mnemonic: “My Old Intel Chip Only Makes Trouble” (Microprocessor, Operand, Instruction, Opcode, ALU, Machine, T-state)

Question 1(c OR) [7 marks]
#

Compare Von-Neumann and Harvard architecture.

Answer:

FeatureVon-Neumann ArchitectureHarvard Architecture
Memory BusesSingle memory bus for instructions and dataSeparate buses for program and data memory
ExecutionSequential executionParallel fetch and execute possible
SpeedSlower due to bus bottleneckFaster due to simultaneous access
ComplexitySimpler designMore complex design
ApplicationsGeneral-purpose computingDSP, microcontrollers, embedded systems
SecurityLess secure (code can be modified as data)More secure (code separation from data)
ExampleMost PCs, 8085, 80868051, PIC, ARM Cortex-M

Diagram:

Von-NCePuUmann:Memory|H|arDvaaCtrPadU:Memory|ProgramMemory|

Mnemonic: “Harvard Has Separate Streets” (Harvard Has Separate memory paths)

Question 2(a) [3 marks]
#

Draw Flag Register of 8085 microprocessor & explain it.

Answer:

Diagram:

S7Z6FLAG5REGA4ICSTE3R(FP2)1C0Y
FlagNamePurpose
SSignSet if result is negative (bit 7=1)
ZZeroSet if result is zero
ACAuxiliary CarrySet if carry from bit 3 to bit 4
PParitySet if result has even parity
CYCarrySet if carry from bit 7 or borrow to bit 7

Mnemonic: “Smart Zombies Always Prefer Candy” (Sign, Zero, Auxiliary, Parity, Carry)

Question 2(b) [4 marks]
#

Explain De-multiplexing of Address and Data buses for 8085 Microprocessor.

Answer:

Diagram:

AA1D57--AA8D08A0L8E5CPUA17L54a-LtASc83h7(3HigherAAd7d-rAe0ss()LowerAddress)
  • Need: 8085 has multiplexed pins (AD0-AD7) to save pins
  • Process:
    1. CPU places address on AD0-AD7 pins
    2. ALE (Address Latch Enable) signal goes HIGH
    3. Address latch (74LS373) captures lower address bits
    4. ALE goes LOW, latching the address
    5. AD0-AD7 pins now free for data transfer

Mnemonic: “ALE Latches, Data Follows” (Address Latch Enable captures address first, then data)

Question 2(c) [7 marks]
#

Describe architecture of 8085 microprocessor with the help of neat diagram.

Answer:

Diagram:

RABSFADE,PldaG(C,adtIA,gAraScDPsLeTc,CUsBEuEsuRm,sS.HB),uLs8085CPUCIDTCMIOneioe/NscmnmOTtoitoRrdnrrDOuegoyeLcrlvt&&iUicNoeInsT
  • Main Components:

    • Registers: Storage locations (A, B-L, SP, PC, Flags)
    • ALU: Performs arithmetic and logical operations
    • Control Unit: Generates timing and control signals
    • Buses: Address bus (16-bit), Data bus (8-bit), Control bus
  • Key Features:

    • 8-bit data bus, 16-bit address bus (64KB addressable memory)
    • 6 general-purpose registers (B,C,D,E,H,L) and accumulator
    • 5 flags for status information

Mnemonic: “RABC” - “Registers, ALU, Buses, Control” (main components)

Question 2(a OR) [3 marks]
#

Explain Bus Organization of 8085 microprocessor.

Answer:

Bus TypeWidthFunction
Address Bus16-bit (A0-A15)Carries memory/I/O device addresses
Data Bus8-bit (D0-D7)Transfers data between CPU & memory/I/O
Control BusVarious signalsCoordinates system operations

Key Control Signals:

  • RD̅: Read signal (active low)
  • WR̅: Write signal (active low)
  • ALE: Address Latch Enable
  • IO/M̅: Distinguishes I/O (high) from memory (low) operations

Diagram:

A(d1d6r-ebsist)BusD(8Ca80Pt-8Uab5iBtu)sCRoDn,tWrRo,lALBEus

Mnemonic: “ADC” - “Address finds, Data travels, Control coordinates”

Question 2(b OR) [4 marks]
#

Explain: Program Counter & Stack pointer

Answer:

RegisterSizeFunction
Program Counter (PC)16-bitHolds address of next instruction to execute
Stack Pointer (SP)16-bitPoints to the top of the stack in memory

Program Counter (PC):

  • Automatically increments after instruction fetch
  • Modified by jump/call instructions
  • Controls program execution sequence
  • Initially set to 0000H on reset

Stack Pointer (SP):

  • Points to last data item pushed onto stack
  • Stack works in LIFO (Last In First Out) manner
  • Used during subroutine calls and interrupts
  • Stack grows downward in memory (decrements)

Diagram:

MemIIDDonnaarssttyttaa:rr1212PSCtED:2ama0cpt0kta1:yHASP:3FFEH

Mnemonic: “PC Previews, SP Stacks” (PC points to next instruction, SP manages stack)

Question 2(c OR) [7 marks]
#

Describe Pin diagram of 8085 microprocessor with the help of neat diagram.

Answer:

Diagram:

AIIDNNIA7HTTRWOA1-RHLRASSDR/LSS5AEODOIME10-D+SLADDA05XED8V1T8085GXRCRRRRTN2ELESSSRDAKSTTTADEPYOT765U...TI555N

Pin Groups:

  1. Power & Clock: Vcc, GND, X1, X2, CLK
  2. Address/Data: A8-A15, AD0-AD7 (multiplexed)
  3. Control: ALE, RD̅, WR̅, IO/M̅
  4. Interrupt: INTR, INTA, RST 5.5/6.5/7.5, TRAP
  5. DMA: HOLD, HLDA
  6. Serial I/O: SID, SOD
  7. Status: S0, S1

Mnemonic: “PACI-DHS” (Power, Address, Control, Interrupt, DMA, Hardware status, Serial)

Question 3(a) [3 marks]
#

Explain Stack, Stack Pointer and Stack operation.

Answer:

TermDefinition
StackMemory area used for temporary storage in LIFO order
Stack Pointer16-bit register that points to the top item in stack
PUSHOperation that stores data on stack (SP decrements)
POPOperation that retrieves data from stack (SP increments)

Diagram:

MBeemfoorrye:PUSH:211S0FFP0FF0FEHHHSPtUaScHk7B6OHp(e7r6aHt)i:onsS:PPOPH:SP

Mnemonic: “LIFO Saves Push-Pop” (Last-In-First-Out with Push and Pop operations)

Question 3(b) [4 marks]
#

Draw Timers/Counters logic diagram of 8051 microcontroller and explain it.

Answer:

Diagram:

CCEolxnottcerkronlalBiItnsputPrescale-rTimer(/CCTooCLLuuooxnnngtttieercrrolMxo-Td-He-x)|TFx(OverflowFlag)
  • 8051 has 2 16-bit timers/counters: Timer 0 and Timer 1
  • Each timer has two 8-bit registers: THx (High byte) and TLx (Low byte)
  • 4 Operating Modes:
    • Mode 0: 13-bit timer
    • Mode 1: 16-bit timer
    • Mode 2: 8-bit auto-reload
    • Mode 3: Split timer mode
  • Two Functions:
    • Timer: Counts internal clock pulses
    • Counter: Counts external events

Mnemonic: “TIME-C” (Timer Input, Mode select, External count)

Question 3(c) [7 marks]
#

With the help of neat diagram explain Pin diagram of 8051 microcontroller.

Answer:

Diagram:

VPPPPPPPPRPPPPPPPPPAC11111111S22222222SLC........T........EE0123456701234567N8051PPPPPPPPPPPPPPPPG33333333XX00000000EN........TT........AD01234567AA01234567LL((((((((21((((((((RTIITTWRAAAAAAAAXXNN01RDDDDDDDDDDDTT))))01234567))01))))))))))

Pin Groups:

  1. Port Pins:
    • P0 (Port 0): 8-bit bidirectional, multiplexed address/data
    • P1 (Port 1): 8-bit bidirectional I/O
    • P2 (Port 2): 8-bit bidirectional, higher address byte
    • P3 (Port 3): 8-bit bidirectional with alternate functions
  2. Power & Clock: VCC, GND, XTAL1, XTAL2
  3. Control Signals:
    • RST: Reset input
    • ALE: Address Latch Enable
    • PSEN: Program Store Enable
    • EA: External Access

Mnemonic: “PORT-CAPS” (Ports 0-3, Clock, Address latch, Program store, Supply)

Question 3(a OR) [3 marks]
#

Explain Serial communication modes of 8051 microcontroller.

Answer:

ModeDescriptionBaud RateData Bits
Mode 0Shift registerFixed (FOSC/12)8 bits
Mode 18-bit UARTVariable10 bits (8+start+stop)
Mode 29-bit UARTFixed (FOSC/32 or FOSC/64)11 bits (9+start+stop)
Mode 39-bit UARTVariable11 bits (9+start+stop)

Key Components:

  • SBUF: Serial buffer register
  • SCON: Serial control register
  • P3.0 (RXD): Receive pin
  • P3.1 (TXD): Transmit pin

Diagram:

Timer1BRGaaeutndeSCLeoorngSitiBarcUloFlTRXXDD

Mnemonic: “SMART” (Serial Modes Are Rate and Timing dependent)

Question 3(b OR) [4 marks]
#

Explain Internal RAM Organization of 8051 microcontroller.

Answer:

Diagram:

8051GReeInBg(neiiRtrts0eaR-At-rlAAreRnMder7aPda)lurBreaRpsnAoskMsaseb(l1e287320bF000yHHHHtes):
Memory RegionAddress RangeDescription
Register Banks00H-1FHFour banks (0-3) of 8 registers each
Bit-Addressable20H-2FH16 bytes (128 bits) individually addressable
General Purpose30H-7FHScratch pad RAM for variables
SFR80H-FFHSpecial Function Registers (not in RAM)

Key Features:

  • Only one register bank active at a time (selected by PSW bits)
  • Each bit in bit-addressable area has its own address (20H.0-2FH.7)
  • Stack can be located anywhere in internal RAM

Mnemonic: “RGB-S” (Registers, General purpose, Bit-addressable, SFRs)

Question 3(c OR) [7 marks]
#

Explain architecture of 8051 microcontroller with the help of neat diagram.

Answer:

Diagram:

IInn(CtRtR4PeAeOKUrMrM)nnaall80C5ToS1iuePmnroAetirRreatCsrlH/sITECETxUtReErnIEIaI/PxnlnO0ttt,eeMePPrrero1nfmrr,aaoutPlcrps2eyt,sP&3|Devices

Key Components:

  • CPU: 8-bit processor with ALU, registers, and control logic
  • Memory:
    • 4KB internal ROM (program memory)
    • 128 bytes internal RAM (data memory)
  • I/O: Four 8-bit I/O ports (P0-P3)
  • Timers: Two 16-bit timers/counters
  • Serial Port: Full-duplex UART
  • Interrupts: Five interrupt sources with two priority levels

Mnemonic: “BASICS” (Bus, Architecture with CPU, Serial port, I/O ports, Counters/timers, Special functions)

Question 4(a) [3 marks]
#

Write an 8051 Assembly Language Program to Exchange lower nibbles of register R5 and R6: put the lower nibble of R5 into R6, and the lower nibble of R6 into R5.

Answer:

      ; Exchange lower nibbles of R5 and R6
      MOV A, R5    ; Copy R5 to accumulator
      ANL A, #0FH  ; Mask upper nibble (keep only lower nibble)
      MOV B, A     ; Save R5's lower nibble in B
      
      MOV A, R6    ; Copy R6 to accumulator
      ANL A, #0FH  ; Mask upper nibble (keep only lower nibble)
      MOV C, A     ; Save temporarily in a free register (R7)
      
      MOV A, R5    ; Get R5 again
      ANL A, #F0H  ; Keep only upper nibble of R5
      ORL A, C     ; Combine with lower nibble from R6
      MOV R5, A    ; Store result back in R5
      
      MOV A, R6    ; Get R6 again
      ANL A, #F0H  ; Keep only upper nibble of R6
      ORL A, B     ; Combine with lower nibble from R5
      MOV R6, A    ; Store result back in R6

Diagram:

IRRn56i::ti10a00l11l01y:10100101RRA56f::te10r0011E01xc01h0F1a1r0n1o0gme:R6

Mnemonic: “MAMS” (Mask, And, Move, Swap)

Question 4(b) [4 marks]
#

Write an 8051 Assembly Language Program to blink LED interfaced at port P1.0 at time interval of 1ms.

Answer:

      ORG 0000H        ; Start at memory location 0000H
MAIN: CPL P1.0         ; Complement P1.0 (toggle LED)
      ACALL DELAY      ; Call delay subroutine
      SJMP MAIN        ; Loop forever

DELAY: MOV R7, #2      ; Load R7 for outer loop (2)
DELAY1: MOV R6, #250   ; Load R6 for inner loop (250)
DELAY2: NOP            ; No operation (consume time)
        NOP            ; Additional delay
        DJNZ R6, DELAY2 ; Decrement R6 & loop until zero
        DJNZ R7, DELAY1 ; Decrement R7 & loop until zero
        RET            ; Return from subroutine

Diagram:

P1.0=11m1smsP1.0=0

Mnemonic: “TCDL” (Toggle, Call, Delay, Loop)

Question 4(c) [7 marks]
#

List Addressing Modes of 8051 Microcontroller and explain them with at least one example.

Answer:

Addressing ModeDescriptionExample
RegisterUses registers (R0-R7)MOV A, R0 (Move R0 to A)
DirectUses direct memory addressMOV A, 30H (Move data from 30H to A)
Register IndirectUses register as pointerMOV A, @R0 (Move data from address in R0 to A)
ImmediateUses constant dataMOV A, #25H (Load A with 25H)
IndexedBase address + offsetMOVC A, @A+DPTR (Code memory access)
BitOperates on individual bitsSETB P1.0 (Set bit 0 of Port 1)
ImpliedImplicit operandRRC A (Rotate A right through carry)

Diagram:

RMeOgVAisAt,erR5R5DMiOrVAecAt,40H40HIMnOdVAirAe,ct@R1RX1=X

Mnemonic: “RIDDIBM” (Register, Immediate, Direct, Data, Indirect, Bit, iMplied)

Question 4(a OR) [3 marks]
#

Write an 8051 Assembly Language Program to add the byte in register R2 and R3, put the result in external RAM 2040h (LSB) and 2041h (MSB).

Answer:

      MOV A, R2      ; Move R2 to accumulator
      ADD A, R3      ; Add R3 to accumulator
      MOV DPTR, #2040H ; Set DPTR to external RAM address 2040H
      MOVX @DPTR, A  ; Store the result (LSB) at 2040H
      
      MOV A, #00H    ; Clear accumulator
      ADDC A, #00H   ; Add carry flag to accumulator
      INC DPTR       ; Increment DPTR to 2041H
      MOVX @DPTR, A  ; Store the result (MSB) at 2041H

Diagram:

R225HADRD345HExt22e00r44n01aHHl::R60AA0M((2N5oHc+ar4r5yH)=6AH)

Mnemonic: “MASIM” (Move, Add, Store, Increment, Move again)

Question 4(b OR) [4 marks]
#

For 8051 Microcontroller with a crystal frequency of 12 MHz, generate a delay of 5ms.

Answer:

      ; Delay of 5ms with 12MHz Crystal (1 machine cycle = 1μs)
DELAY: MOV R7, #5     ; 5 loops of 1ms each
LOOP1: MOV R6, #250   ; 250 x 4μs = 1000μs = 1ms
LOOP2: NOP            ; 1μs
       NOP            ; 1μs
       DJNZ R6, LOOP2 ; 2μs (if jump taken)
       DJNZ R7, LOOP1 ; Repeat 5 times for 5ms
       RET            ; Return from subroutine

Diagram:

RR2DDR76eeeSNcctt==OrruaPeerr52smmnt5ee0nnttRR67

Calculation:

  • 12MHz crystal = 1μs machine cycle
  • Inner loop: 2 NOPs (2μs) + DJNZ (2μs) = 4μs per iteration
  • 250 iterations × 4μs = 1000μs = 1ms
  • Outer loop: 5 iterations × 1ms = 5ms

Mnemonic: “LOON-5” (LOOp Nested for 5ms)

Question 4(c OR) [7 marks]
#

Explain any seven Arithmetic Instructions with example for 8051 Microcontroller.

Answer:

InstructionFunctionExampleFlag Affected
ADD A,srcAdd source to AADD A,R0 (A=A+R0)C, OV, AC
ADDC A,srcAdd source + carry to AADDC A,#25H (A=A+25H+C)C, OV, AC
SUBB A,srcSubtract source + borrow from ASUBB A,@R1 (A=A-@R1-C)C, OV, AC
INCIncrement by 1INC R3 (R3=R3+1)None
DECDecrement by 1DEC A (A=A-1)None
MUL ABMultiply A and BMUL AB (B:A=A×B)C, OV
DIV ABDivide A by BDIV AB (A=quotient, B=remainder)C, OV

Diagram:

AAAADD===A223,55ARHHH0,+R015=H15HMABBU:L=A=A0=0B50H0H,5,HBA×==00303HFHHDAAAIV===A110B444HHH,,÷BB0=5=H0050HH

Mnemonic: “ACID-IBM” (Add, Carry add, Inc, Dec, Mul, Borrow subtract, Divide)

Question 5(a) [3 marks]
#

List Applications of microcontroller in various fields.

Answer:

FieldApplications
Consumer ElectronicsTV, washing machine, microwave, remote control
AutomotiveEngine control, anti-lock braking, airbag systems
IndustrialAutomation, robotics, process control
MedicalPatient monitoring, medical instruments, implants
Home AutomationSmart lighting, security systems, HVAC control
CommunicationMobile phones, routers, modems
AerospaceNavigation systems, flight control, satellite systems

Diagram:

CEASoluynetsscotutmemromeotsrniivcesMAIAMDipnueecpdtdvrluoiioismcccctaaeoartlsntiitiaorolnonlslerCSHAoyoumsmtmteouemnmaistciaotnion

Mnemonic: “CHAIM-MA” (Consumer, Home, Automotive, Industrial, Medical, Mobile, Aerospace)

Question 5(b) [4 marks]
#

Interface Relay with 8051 microcontroller.

Answer:

Diagram:

8051-P1.0--DUrLiNv2e0r0+35VProDtieocdteionRelayCoil

Components Required:

  • 8051 microcontroller
  • ULN2003 or similar driver IC
  • Relay (5V or 12V)
  • Protection diode (1N4007)
  • Power supply

Working:

  1. 8051 sends control signal from P1.0
  2. Driver amplifies current to drive relay
  3. Protection diode prevents back EMF damage
  4. Relay switches connected devices

Mnemonic: “DRIPS” (Driver, Relay, Input from µC, Protection diode, Switching)

Question 5(c) [7 marks]
#

Interface LCD with 8051 microcontroller.

Answer:

Diagram:

8051PPPPPPPPPPP11122222222...........01201234567RREDDDDDDDDS/012345671WVPG6CoNxCtD2LCD

Connections:

  • Control Lines:
    • P1.0 → RS (Register Select)
    • P1.1 → R/W (Read/Write)
    • P1.2 → E (Enable)
  • Data Lines:
    • P2.0-P2.7 → D0-D7 (8-bit data bus)

Code to Initialize LCD:

MOV A, #38H      ; 2 lines, 5x7 matrix
ACALL COMMAND    ; Send command

MOV A, #0EH      ; Display ON, cursor ON
ACALL COMMAND    ; Send command

MOV A, #01H      ; Clear LCD
ACALL COMMAND    ; Send command

MOV A, #06H      ; Increment cursor
ACALL COMMAND    ; Send command

Mnemonic: “CIDER-8” (Control lines, Initialize, Data bus, Enable, Register select, 8-bit mode)

Question 5(a OR) [3 marks]
#

Draw Interfacing of LED with 8051 microcontroller.

Answer:

Diagram:

L+E85RDP0V15(.12020Ω)

Components:

  • 8051 microcontroller
  • LED
  • Current limiting resistor (220Ω)
  • Power supply

Working Principle:

  • Active-Low configuration: LED ON when pin = 0
  • P1.0 drives LED through current limiting resistor
  • Maximum current should not exceed 20mA per pin

Code for LED Blinking:

MAIN: CLR P1.0    ; Turn ON LED (active low)
      CALL DELAY  ; Wait
      SETB P1.0   ; Turn OFF LED
      CALL DELAY  ; Wait
      SJMP MAIN   ; Repeat

Mnemonic: “CIRCLE” (Current limiting Resistor, IO pin, Cathode to LED, LED to Earth/ground)

Question 5(b OR) [4 marks]
#

Interface DC Motor with 8051 microcontroller.

Answer:

Diagram:

8051--PP11..01---->>LMD2or+9ti53ovVDrer--OOuutt12----MDoCtor

Components:

  • 8051 microcontroller
  • L293D motor driver IC
  • DC motor
  • Power supply

Control Logic:

P1.0P1.1Motor Action
00Stop (Brake)
01Clockwise
10Counter-clockwise
11Stop (Free-running)

Code for Motor Control:

MOV P1, #02H  ; P1.0=0, P1.1=1 (Clockwise)
CALL DELAY    ; Run for some time
MOV P1, #01H  ; P1.0=1, P1.1=0 (Counter-clockwise)
CALL DELAY    ; Run for some time
MOV P1, #00H  ; P1.0=0, P1.1=0 (Stop)

Mnemonic: “DICER” (Driver chip, Input from µC, Control logic, Enable motor, Rotation)

Question 5(c OR) [7 marks]
#

Interface DAC0808 with 8051 microcontroller.

Answer:

Diagram:

8051--PP13..00--P-1-.-7----->>DC0DS-+G-A55NDCVVD70808-Output--FilterAOnuatlpougt

Components:

  • 8051 microcontroller
  • DAC0808 (8-bit digital-to-analog converter)
  • Operational amplifier (for output buffering)
  • RC filter (for smoothing)
  • Reference voltage source

Connections:

  • P1.0-P1.7 → D0-D7 (8-bit digital input)
  • P3.0 → CS (Chip Select)
  • DAC output → filter → final analog output

Sample Code for Ramp Signal Generation:

START: MOV R0, #00H      ; Start from 0
LOOP:  MOV P1, R0        ; Output value to DAC
       CALL DELAY        ; Wait
       INC R0            ; Increment value
       SJMP LOOP         ; Loop to create ramp

Applications:

  • Waveform generation
  • Programmable voltage source
  • Motor speed control
  • Audio applications

Mnemonic: “DACR” (Digital input, Analog output, Conversion, Reference voltage)

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