Question 1(a) [3 marks]#
Give comparison between transmission line and waveguide.
Answer:
Parameter | Transmission Line | Waveguide |
---|---|---|
Frequency Range | Low to medium frequencies | High frequencies (above 1 GHz) |
Structure | Two or more conductors | Single hollow conductor |
Propagation Mode | TEM mode | TE and TM modes |
Power Handling | Limited power capacity | High power handling capability |
Losses | Higher losses at high frequencies | Lower losses at microwave frequencies |
Mnemonic: “WAVES Travel Better” (Waveguides - Advanced Versions Enabling Superior Transmission)
Question 1(b) [4 marks]#
Define the following terms: (1) Lossless Line (2) VSWR (3) STUB (4) Reflection coefficient
Answer:
Lossless Line: A transmission line with zero resistance and conductance, having no power loss during signal transmission.
VSWR (Voltage Standing Wave Ratio): Ratio of maximum voltage to minimum voltage on a transmission line, indicating impedance mismatch.
STUB: Short length of transmission line connected to main line for impedance matching purposes.
Reflection Coefficient: Ratio of reflected wave amplitude to incident wave amplitude at any point on transmission line.
Mnemonic: “Light Volumes Stay Reflected” (Lossless-VSWR-Stub-Reflection)
Question 1(c) [7 marks]#
Explain isolator and circulator with the help of sketch.
Answer:
graph LR
A[Port 1] --> B[Isolator] --> C[Port 2]
B -.X.-> A
D[Port 1] --> E((Circulator)) --> F[Port 2]
F --> G[Port 3] --> D
Isolator:
- Function: Allows signal flow in one direction only
- Construction: Uses ferrite material with magnetic bias
- Applications: Protects sources from reflections
Circulator:
- Function: Routes signals in circular pattern between three or four ports
- Construction: Y-junction with ferrite material
- Applications: Duplexers in radar systems
Mnemonic: “Isolated Circuits Flow Forward” (Isolator-Circulator-Forward-Flow)
Question 1(c OR) [7 marks]#
What is dominant mode in a waveguide? What will be the cutoff wavelength for dominant mode, in a rectangular waveguide whose breadth is 10 cm? For a 2.5 GHz signal propagated through it calculate guide wavelength, group velocity and phase velocity and Z₀.
Answer:
Dominant Mode: Lowest order mode that can propagate in a waveguide. For rectangular waveguide, it’s TE₁₀ mode.
Given Data:
- Breadth (a) = 10 cm = 0.1 m
- Frequency (f) = 2.5 GHz = 2.5 × 10⁹ Hz
- c = 3 × 10⁸ m/s
Calculations:
Parameter | Formula | Value |
---|---|---|
Cutoff Wavelength | λc = 2a | λc = 2 × 0.1 = 0.2 m |
Free Space Wavelength | λ₀ = c/f | λ₀ = 0.12 m |
Guide Wavelength | λg = λ₀/√(1-(λ₀/λc)²) | λg = 0.133 m |
Group Velocity | vg = c√(1-(λ₀/λc)²) | vg = 2.7 × 10⁸ m/s |
Phase Velocity | vp = c/√(1-(λ₀/λc)²) | vp = 3.33 × 10⁸ m/s |
Mnemonic: “Dominant Modes Calculate Guide Parameters”
Question 2(a) [3 marks]#
What is single stub impedance matching, and how does it work?
Answer:
Single Stub Matching: Technique using one short-circuited or open-circuited stub connected in parallel to transmission line for impedance matching.
Working Principle:
- Stub acts as reactive element (inductive or capacitive)
- Cancels reactive component of load impedance
- Transforms impedance to characteristic impedance
Mnemonic: “Single Stubs Transform Reactance” (Single-Stub-Transform-Reactive)
Question 2(b) [4 marks]#
Differentiate between rectangular and circular waveguide any three points.
Answer:
Parameter | Rectangular Waveguide | Circular Waveguide |
---|---|---|
Cross-section | Rectangular shape | Circular shape |
Dominant Mode | TE₁₀ mode | TE₁₁ mode |
Field Pattern | Simple field distribution | Complex field distribution |
Manufacturing | Easy to manufacture | Difficult to manufacture |
Mnemonic: “Rectangles Dominate Ten” vs “Circles Dominate Eleven”
Question 2(c) [7 marks]#
Explain the construction and working of Hybrid Ring with diagram.
Answer:
graph TD
A[Port 1] --- B[Hybrid Ring]
C[Port 2] --- B
D[Port 3] --- B
E[Port 4] --- B
B -.-> F[λ/4 sections]
Construction:
- Ring structure with four ports
- Circumference = 1.5λ (one and half wavelengths)
- Adjacent ports separated by λ/4
- Opposite ports separated by 3λ/4
Working:
- Power division: Input at one port divides equally between two adjacent ports
- Isolation: Opposite port receives no power
- Phase relationship: 180° phase difference between output ports
Applications:
- Balanced mixers
- Power combiners/dividers
- Antenna feeds
Mnemonic: “Hybrid Rings Divide Power Equally”
Question 2(a OR) [3 marks]#
What is Microwave? List out any four applications of microwave.
Answer:
Microwave: Electromagnetic waves with frequency range from 1 GHz to 300 GHz.
Applications:
- Radar systems for detection and ranging
- Satellite communication for long-distance transmission
- Microwave ovens for heating food
- Mobile communication (cellular networks)
Mnemonic: “Microwaves Reach Space Mobile” (Microwave-Radar-Satellite-Mobile)
Question 2(b OR) [4 marks]#
Write short note on cavity resonator.
Answer:
Cavity Resonator: Closed metallic structure that confines electromagnetic energy at specific resonant frequencies.
Construction:
- Metallic enclosure of specific dimensions
- High Q factor (low losses)
- Resonant frequency depends on cavity dimensions
Types:
- Rectangular cavity
- Cylindrical cavity
- Spherical cavity
Applications:
- Frequency meters
- Oscillator circuits
- Filter circuits
Mnemonic: “Cavities Resonate High Quality” (Cavity-Resonant-High-Q)
Question 2(c OR) [7 marks]#
Explain MAGIC TEE with the help of sketch and how it works as an isolator?
Answer:
graph TD
A[E-arm] --- B[Magic Tee Junction]
C[H-arm] --- B
D[Arm 1] --- B
E[Arm 2] --- B
Magic Tee Construction:
- E-plane Tee and H-plane Tee combined
- Four ports: E-arm, H-arm, and two side arms
- E-arm perpendicular to H-arm
Working as Isolator:
- Signal at E-arm divides equally between side arms (in-phase)
- Signal at H-arm divides equally between side arms (out-of-phase)
- Isolation between E-arm and H-arm
- No coupling between perpendicular arms
Properties:
- Matched at all ports
- Reciprocal device
- Power division and isolation
Mnemonic: “Magic Isolates Perpendicular Arms”
Question 3(a) [3 marks]#
Describe the working principle of MASER.
Answer:
MASER (Microwave Amplification by Stimulated Emission of Radiation):
- Population inversion created in active medium
- Stimulated emission produces coherent microwaves
- Amplification occurs through energy level transitions
Working Principle:
- Atoms excited to higher energy levels
- Stimulated photons trigger emission
- Coherent amplification of microwave signals
Mnemonic: “Microwaves Amplify Stimulated Emission Radiation”
Question 3(b) [4 marks]#
List four microwave diodes and explain any one.
Answer:
Four Microwave Diodes:
- GUNN Diode
- IMPATT Diode
- TRAPATT Diode
- PIN Diode
GUNN Diode Explanation:
- Principle: Transferred electron effect in GaAs
- Construction: N-type GaAs with ohmic contacts
- Operation: Negative resistance at microwave frequencies
- Applications: Oscillators, amplifiers
VI Characteristic:
Mnemonic: “GUNN Generates Negative Resistance”
Question 3(c) [7 marks]#
Write a detailed explanation of the Magnetron Oscillator, covering its construction, working principle, and applications?
Answer:
graph LR
A[Cathode] --> B[Interaction Space]
B --> C[Anode with Cavities]
C --> D[Output Coupling]
E[Magnetic Field] -.-> B
Construction:
- Cylindrical cathode at center
- Anode with resonant cavities surrounding cathode
- Strong magnetic field perpendicular to electric field
- Output coupling through waveguide
Working Principle:
- Electrons emitted from heated cathode
- Cycloid motion due to crossed E and B fields
- Bunching effect creates electron clouds
- Energy transfer from electrons to RF field
- Oscillation at cavity resonant frequency
Applications:
- Radar transmitters
- Microwave ovens
- Industrial heating
- Medical diathermy
Mnemonic: “Magnetrons Make Microwave Oscillations”
Question 3(a OR) [3 marks]#
Describe the working of RUBY MASER.
Answer:
Ruby MASER Working:
- Ruby crystal (Al₂O₃ with Cr³⁺ ions) as active medium
- Three energy levels in chromium ions
- Pump frequency creates population inversion
- Signal amplification at 2.9 GHz
Process:
- Optical pumping excites electrons to higher level
- Stimulated emission produces coherent microwaves
- Low noise amplification achieved
Mnemonic: “Ruby Radiates Amplified Microwaves”
Question 3(b OR) [4 marks]#
Draw and explain the VI characteristic of Gun diode
Answer:
VI Characteristic Explanation:
- Region OA: Ohmic region (positive resistance)
- Region AB: Negative resistance region
- Region BC: Valley current region
- Region CD: Saturation region
Key Points:
- Peak voltage: Maximum voltage before negative resistance
- Valley current: Minimum current in negative resistance region
- Negative resistance: Current decreases with increasing voltage
Mnemonic: “Valley Peak Negative Resistance”
Question 3(c OR) [7 marks]#
Explain “frequency measurement method” as well as “attenuation measurement method” at microwave frequency.
Answer:
Frequency Measurement Methods:
Method | Principle | Accuracy |
---|---|---|
Cavity Wavemeter | Resonant cavity tuning | High |
Direct Reading Meter | Frequency counter | Very High |
Heterodyne Method | Beat frequency technique | Medium |
Attenuation Measurement Methods:
Method | Description | Application |
---|---|---|
Substitution Method | Replace attenuator with calibrated attenuator | Precision measurement |
Power Ratio Method | Compare input and output power | General purpose |
RF Bridge Method | Balance bridge circuit | Laboratory use |
Setup for Measurement:
- Signal generator provides test signal
- Calibrated attenuator for reference
- Power meter measures signal levels
- VSWR meter monitors impedance matching
Mnemonic: “Frequency Attenuation Measured Precisely”
Question 4(a) [3 marks]#
Explain working of P-i-N diode.
Answer:
P-i-N Diode Structure:
- P-type region (heavily doped)
- Intrinsic region (undoped, high resistance)
- N-type region (heavily doped)
Working:
- Forward bias: Low resistance, acts as conductor
- Reverse bias: High resistance, acts as insulator
- RF switching: Fast switching due to charge storage
Applications:
- RF switches
- Attenuators
- Phase shifters
Mnemonic: “PIN Provides Instant Switching”
Question 4(b) [4 marks]#
Explain π mode oscillations for magnetron.
Answer:
π Mode Oscillation:
- Adjacent cavities oscillate 180° out of phase
- Electron bunching synchronized with RF field
- Maximum power transfer from electrons to RF
- Stable oscillation at designed frequency
Characteristics:
- Phase difference: π radians between adjacent cavities
- Frequency: Determined by cavity dimensions
- Efficiency: Highest among all modes
- Stability: Most stable oscillation mode
Mode Chart:
Mnemonic: “Pi Mode Produces Maximum Power”
Question 4(c) [7 marks]#
Explain the construction and working of two cavity klystron amplifiers with necessary diagram.
Answer:
graph LR
A[Electron Gun] --> B[Input Cavity]
B --> C[Drift Space]
C --> D[Output Cavity]
D --> E[Collector]
F[Input Signal] --> B
D --> G[Output Signal]
Construction:
- Electron gun produces electron beam
- Input cavity (buncher) modulates electron beam
- Drift space allows velocity modulation
- Output cavity (catcher) extracts RF energy
- Collector collects spent electrons
Working Principle:
- Velocity modulation in input cavity
- Electron bunching in drift space
- Density modulation creates current variation
- Energy extraction in output cavity
- Amplification achieved through beam-field interaction
Key Parameters:
- Beam voltage: Determines electron velocity
- Cavity tuning: Sets operating frequency
- Drift space length: Controls bunching effectiveness
Applications:
- Radar transmitters
- Satellite communication
- Linear accelerators
Mnemonic: “Klystrons Amplify Through Bunching”
Question 4(a OR) [3 marks]#
Explain parametric amplifier.
Answer:
Parametric Amplifier:
- Variable reactance device using varactor diode
- Pump frequency modulates diode capacitance
- Energy transfer from pump to signal
- Low noise amplification achieved
Working:
- Pump power varies diode reactance
- Signal mixing produces sum and difference frequencies
- Idler frequency fp = fs + fi
- Power gain through nonlinear mixing
Advantages:
- Very low noise figure
- High gain possible
- Wide bandwidth
Mnemonic: “Parametric Amplifiers Pump Low Noise”
Question 4(b OR) [4 marks]#
Draw and explain schematic diagram of travelling wave tube with necessary notation
Answer:
graph LR
A[Electron Gun] --> B[Input]
B --> C[Helix]
C --> D[Output]
D --> E[Collector]
F[Attenuator] -.-> C
G[Focusing System] -.-> C
Components:
- Electron gun: Produces electron beam
- Helix: Slow-wave structure
- Attenuator: Prevents oscillation
- Collector: Collects electrons
- Focusing system: Maintains beam alignment
Working:
- Electron beam travels through helix center
- RF signal propagates along helix
- Synchronism between beam and RF wave
- Energy transfer from beam to RF
- Continuous amplification along helix length
Mnemonic: “TWT Travels With Waves”
Question 4(c OR) [7 marks]#
Explain the working principle of a reflex klystron in detail with suitable diagram.
Answer:
graph LR
A[Cathode] --> B[Resonant Cavity]
B --> C[Drift Space]
C --> D[Repeller]
D -.-> C
C -.-> B
B --> E[Output]
Construction:
- Single resonant cavity acts as buncher and catcher
- Repeller electrode reflects electron beam
- Drift space allows velocity modulation
- Output coupling extracts RF power
Working Principle:
Applegate Diagram:
Process:
- Electrons enter cavity and get velocity modulated
- Electrons drift toward repeller
- Repeller reflects electrons back to cavity
- Transit time determines bunching phase
- Bunched electrons deliver energy to cavity
- Oscillation maintained through feedback
Frequency Tuning:
- Repeller voltage controls transit time
- Cavity tuning sets center frequency
- Electronic tuning possible
Applications:
- Local oscillators
- Frequency meters
- Microwave sources
Mnemonic: “Reflex Returns Electron Bunches”
Question 5(a) [3 marks]#
“PIN diode acts as a switch and VARACTOR diode acts as a variable capacitor” explain.
Answer:
PIN Diode as Switch:
- Forward bias: Low resistance (~1Ω), switch ON
- Reverse bias: High resistance (~10kΩ), switch OFF
- Fast switching due to charge storage in I-region
- RF isolation in OFF state
VARACTOR Diode as Variable Capacitor:
- Reverse bias voltage controls junction capacitance
- Capacitance decreases with increasing reverse voltage
- Voltage-controlled reactance for tuning circuits
- Electronic tuning without mechanical adjustment
Mnemonic: “PIN Switches, VARACTOR Varies”
Question 5(b) [4 marks]#
List the display methods used in RADAR and explain any one.
Answer:
RADAR Display Methods:
- A-Scope Display
- PPI (Plan Position Indicator)
- B-Scope Display
- RHI (Range Height Indicator)
PPI Display Explanation:
- Circular display showing target positions
- Center represents radar location
- Radial distance indicates target range
- Angular position shows target bearing
- Rotating sweep synchronized with antenna rotation
Features:
- Real-time display of target positions
- Range and bearing information
- Multiple target tracking
- Clutter suppression
Mnemonic: “PPI Pictures Position Indicators”
Question 5(c) [7 marks]#
What is radar? List out the different types of radar systems? Explain any One of radar in detail?
Answer:
RADAR (Radio Detection And Ranging): System using radio waves to detect objects and determine their range, velocity, and characteristics.
Types of RADAR Systems:
Type | Application | Frequency Band |
---|---|---|
Pulse Radar | Air traffic control | L, S, C bands |
CW Doppler Radar | Speed measurement | X, K, Ka bands |
MTI Radar | Moving target detection | S, C bands |
SAR Radar | Ground mapping | L, C, X bands |
Pulse Radar Detailed Explanation:
graph LR
A[Transmitter] --> B[Duplexer]
B --> C[Antenna]
C --> D[Target]
D --> C
C --> B
B --> E[Receiver]
E --> F[Display]
G[Timer] --> A
G --> F
Working:
- Transmits short pulses of RF energy
- Receives echoes from targets
- Measures time delay for range calculation
- Processes signals for display
Range Equation: R = (c × t)/2
Where:
- R = Range to target
- c = Speed of light
- t = Time delay
Applications:
- Air traffic control
- Weather monitoring
- Military surveillance
- Navigation aids
Mnemonic: “Radar Ranges Radio Waves”
Question 5(a OR) [3 marks]#
Describe the operation of TRAPATT diode with diagram.
Answer:
TRAPATT Operation:
- TRApped Plasma Avalanche Triggered Transit diode
- High field region creates avalanche breakdown
- Plasma formation traps charge carriers
- Transit time effects create negative resistance
- Oscillation frequency determined by transit time
Applications:
- High power oscillators
- Radar transmitters
- Communication systems
Mnemonic: “TRAPATT Traps Plasma Avalanche”
Question 5(b OR) [4 marks]#
Compare RADAR with SONAR.
Answer:
Parameter | RADAR | SONAR |
---|---|---|
Wave Type | Electromagnetic waves | Sound waves |
Medium | Air/vacuum | Water/liquid |
Frequency | GHz range | kHz range |
Speed | 3 × 10⁸ m/s | 1500 m/s in water |
Range | Very long range | Limited by absorption |
Applications | Air/space detection | Underwater detection |
Similarities:
- Echo principle for detection
- Range measurement using time delay
- Doppler effect for velocity measurement
Mnemonic: “RADAR Radiates, SONAR Sounds”
Question 5(c OR) [7 marks]#
Obtain the equation for maximum radar range.
Answer:
RADAR Range Equation Derivation:
Power Transmitted: Pt
Power Density at Target: Pd = Pt/(4πR²)
Power Intercepted by Target: Pi = Pd × σ = (Pt × σ)/(4πR²)
Power Returned to Radar: Pr = Pi/(4πR²) = (Pt × σ)/(4πR²)²
Power Received: Pr = (Pt × G² × λ² × σ)/((4π)³ × R⁴)
Maximum Range Equation:
Rmax = ⁴√[(Pt × G² × λ² × σ)/((4π)³ × Prmin)]
Where:
- Pt = Transmitted power
- G = Antenna gain
- λ = Wavelength
- σ = Radar cross section
- Prmin = Minimum detectable signal
- R = Range
Factors Affecting Range:
- Transmitted power (increases range)
- Antenna gain (increases range)
- Target cross-section (increases range)
- Frequency (affects propagation)
- Receiver sensitivity (affects minimum signal)
Practical Considerations:
- Atmospheric losses
- Ground reflections
- Noise limitations
- Clutter effects
Mnemonic: “Power Gain Lambda Sigma Range”