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Computer Networks & Data Communication (4361101) - Summer 2024 Solution

16 mins· ·
Study-Material Solutions Computer-Networks 4361101 2024 Summer
Milav Dabgar
Author
Milav Dabgar
Experienced lecturer in the electrical and electronic manufacturing industry. Skilled in Embedded Systems, Image Processing, Data Science, MATLAB, Python, STM32. Strong education professional with a Master’s degree in Communication Systems Engineering from L.D. College of Engineering - Ahmedabad.
Table of Contents

Question 1(a) [3 marks]
#

List the different Network Topologies and discuss any one in detail.

Answer:

TopologyDescription
StarAll devices connected to central hub/switch
RingDevices connected in circular fashion
BusAll devices connected to single cable
MeshEvery device connected to every other device
TreeHierarchical structure with root node
HybridCombination of two or more topologies

Star Topology Details:

  • Central Hub: All nodes connect to one central device
  • Point-to-Point: Each connection is dedicated between node and hub
  • Easy Management: Simple to install and troubleshoot

Mnemonic: “STAR = Single Terminal All Reach”

Question 1(b) [4 marks]
#

Explain how point-to-point and broadcast transmission technologies are used in modern communication systems with examples of real-world applications and discuss their advantages and limitations.

Answer:

TechnologyPoint-to-PointBroadcast
ConnectionDirect link between two devicesOne-to-many communication
ExampleTelephone, VPN tunnelsRadio, TV, WiFi
Data FlowBidirectionalUnidirectional/Multidirectional

Point-to-Point Applications:

  • Dedicated Lines: Leased lines between offices
  • Satellite Links: Ground station to satellite communication
  • Cable Modems: Home to ISP connection

Broadcast Applications:

  • WiFi Networks: Router broadcasts to multiple devices
  • Television: One transmitter to many receivers

Mnemonic: “P2P = Private Path, Broadcast = Big Audience”

Question 1(c) [7 marks]
#

Describe OSI model with function of all layers.

Answer:

LayerNameFunction
7ApplicationUser interface, network services
6PresentationData encryption, compression, formatting
5SessionEstablishes, manages, terminates sessions
4TransportReliable data transfer, error correction
3NetworkRouting, logical addressing (IP)
2Data LinkFrame formatting, error detection
1PhysicalBit transmission, electrical signals
graph TD
    A[Application Layer 7] --> B[Presentation Layer 6]
    B --> C[Session Layer 5]
    C --> D[Transport Layer 4]
    D --> E[Network Layer 3]
    E --> F[Data Link Layer 2]
    F --> G[Physical Layer 1]

Key Functions:

  • Upper Layers (5-7): Handle application-related services
  • Lower Layers (1-4): Handle data transmission and routing
  • Encapsulation: Each layer adds its own header

Mnemonic: “All People Seem To Need Data Processing”

Question 1(c OR) [7 marks]
#

Write a functional description of all layer of TCP/IP model.

Answer:

LayerNameFunctionProtocols
4ApplicationUser services, applicationsHTTP, FTP, SMTP, DNS
3TransportEnd-to-end communicationTCP, UDP
2InternetRouting, logical addressingIP, ICMP, ARP
1Network AccessPhysical transmissionEthernet, WiFi
graph TD
    A[Application Layer] --> B[Transport Layer]
    B --> C[Internet Layer]
    C --> D[Network Access Layer]

Layer Functions:

  • Application: Provides network services to applications
  • Transport: Ensures reliable or unreliable delivery
  • Internet: Routes packets across networks using IP addresses
  • Network Access: Handles physical transmission media

Mnemonic: “Applications Transport Internet Networks”

Question 2(a) [3 marks]
#

Describe Function of firewall in network security.

Answer:

Firewall Functions:

  • Packet Filtering: Controls incoming and outgoing network traffic
  • Access Control: Blocks unauthorized access attempts
  • Traffic Monitoring: Logs and analyzes network activity

Types:

  • Hardware Firewall: Physical device protecting entire network
  • Software Firewall: Program installed on individual computers
  • Stateful Inspection: Tracks connection states and contexts

Mnemonic: “Firewall = Filter, Access, Monitor”

Question 2(b) [4 marks]
#

Compare FDDI (Fiber Distributed Data Interface) and CDDI (Copper Distributed Data Interface) in terms of their key characteristics, advantages, and applications.

Answer:

FeatureFDDICDDI
MediumOptical fiberTwisted pair copper
Speed100 Mbps100 Mbps
DistanceUp to 200 kmUp to 100 meters
CostHigherLower
SecurityHigher (difficult to tap)Lower (easier to tap)
InstallationComplexSimple

FDDI Advantages:

  • Long Distance: Supports campus-wide networks
  • High Security: Immune to electromagnetic interference
  • Reliability: Better error detection and recovery

CDDI Advantages:

  • Cost Effective: Uses existing copper infrastructure
  • Easy Installation: Standard twisted pair cabling
  • Compatibility: Works with existing network equipment

Mnemonic: “FDDI = Fiber Distance, CDDI = Copper Cost”

Question 2(c) [7 marks]
#

Explain and distinguish Ethernet, Fast Ethernet, Gigabit Ethernet.

Answer:

TypeSpeedStandardCable TypeDistance
Ethernet10 Mbps802.3Coax/UTP100m
Fast Ethernet100 Mbps802.3uUTP Cat5100m
Gigabit Ethernet1000 Mbps802.3z/abCat5e/6, Fiber100m/5km
graph LR
    A[Ethernet 10 Mbps] --> B[Fast Ethernet 100 Mbps]
    B --> C[Gigabit Ethernet 1000 Mbps]

Key Differences:

  • Speed Evolution: 10x increase at each generation
  • Media Support: From coax to twisted pair to fiber
  • Applications: LAN backbone, server connections, desktop
  • Backward Compatibility: Newer standards support older devices

Standards:

  • 10Base-T: 10 Mbps over twisted pair
  • 100Base-TX: 100 Mbps over Category 5 UTP
  • 1000Base-T: 1 Gbps over Category 5e/6 UTP

Mnemonic: “Every Fast Gigabit = 10, 100, 1000”

Question 2(a OR) [3 marks]
#

Explain its role and function of router within a network infrastructure.

Answer:

Router Functions:

  • Packet Forwarding: Routes data packets between different networks
  • Path Determination: Selects best route using routing tables
  • Network Isolation: Separates broadcast domains

Key Roles:

  • Inter-network Communication: Connects LANs to WANs
  • Traffic Management: Controls data flow between networks
  • Protocol Translation: Converts between different network protocols

Mnemonic: “Router = Route, Isolate, Connect”

Question 2(b OR) [4 marks]
#

Explain the structure of FDDI (Fiber Distributed Data Interface) and give its advantages.

Answer:

FDDI Structure:

NNPSooreddiceemoanADrdyarRyinRgi:ngC:lNNoCoocoddkueewnitBCseer-clockwise

Components:

  • Dual Ring: Primary and secondary rings for redundancy
  • Token Passing: Uses token for media access control
  • Concentrators: Connect multiple stations to ring

Advantages:

  • High Reliability: Dual ring provides fault tolerance
  • Fast Speed: 100 Mbps data transmission rate
  • Long Distance: Supports up to 200 km ring circumference
  • Self-Healing: Automatic reconfiguration when link fails

Mnemonic: “FDDI = Fast, Dual, Distance, Immune”

Question 2(c OR) [7 marks]
#

Explain roll of network Devices. Describe in brief about all the devices.

Answer:

DeviceLayerFunction
RepeaterPhysicalRegenerates signals, extends distance
HubPhysicalConnects multiple devices, shared bandwidth
BridgeData LinkConnects LANs, reduces collisions
SwitchData LinkIntelligent hub, dedicated bandwidth
RouterNetworkConnects different networks, routing
GatewayAll LayersProtocol conversion, network interconnection
graph TD
    A[Physical Layer] --> B[Repeater, Hub]
    C[Data Link Layer] --> D[Bridge, Switch]
    E[Network Layer] --> F[Router]
    G[All Layers] --> H[Gateway]

Device Functions:

  • Repeater: Amplifies and regenerates signals
  • Hub: Simple connection point for multiple devices
  • Bridge: Intelligent forwarding based on MAC addresses
  • Switch: High-performance bridge with multiple ports
  • Router: Intelligent path selection between networks
  • Gateway: Complete protocol stack conversion

Mnemonic: “Repeat, Hub, Bridge, Switch, Route, Gateway”

Question 3(a) [3 marks]
#

Name any three data link layer protocol and explain any one in detail.

Answer:

Data Link Layer Protocols:

  • HDLC (High-Level Data Link Control)
  • PPP (Point-to-Point Protocol)
  • Ethernet (IEEE 802.3)

HDLC Protocol Details:

  • Frame Structure: Flag, Address, Control, Data, FCS, Flag
  • Error Detection: Frame Check Sequence (FCS)
  • Flow Control: Sliding window mechanism

HDLC Frame Format:

F8lbaigtA8dbdirtC8tbriltData1F6CbSitF8lbaigt

Mnemonic: “HDLC = High Data Link Control”

Question 3(b) [4 marks]
#

Explain error control and flow control at data link layer

Answer:

Control TypePurposeMethods
Error ControlDetect and correct transmission errorsCRC, Checksum, Parity
Flow ControlManage data transmission rateStop-and-Wait, Sliding Window

Error Control Methods:

  • Detection: CRC, Checksum identify errors
  • Correction: ARQ (Automatic Repeat Request)
  • Prevention: Forward Error Correction (FEC)

Flow Control Methods:

  • Stop-and-Wait: Send one frame, wait for ACK
  • Sliding Window: Send multiple frames before ACK
  • Buffer Management: Prevent receiver overflow

Mnemonic: “Error = Detect, Flow = Control”

Question 3(c) [7 marks]
#

Compare IPv6 and IPv4.

Answer:

FeatureIPv4IPv6
Address Length32 bits128 bits
Address Space4.3 billion340 undecillion
Header Size20-60 bytes (variable)40 bytes (fixed)
NotationDecimal (192.168.1.1)Hexadecimal (2001:db8::1)
FragmentationRouter and hostHost only
SecurityOptional (IPSec)Built-in (IPSec)
ConfigurationManual/DHCPAuto-configuration

IPv4 Example: 192.168.1.100 IPv6 Example: 2001:0db8:85a3:0000:0000:8a2e:0370:7334

Key Differences:

  • Address Exhaustion: IPv4 addresses nearly exhausted
  • Header Efficiency: IPv6 simplified header structure
  • Security: IPv6 has built-in security features
  • Quality of Service: Better QoS support in IPv6

Mnemonic: “IPv6 = Infinite, Integrated, Improved”

Question 3(a OR) [3 marks]
#

Explain the differences between guided and unguided transmission media used in computer networks

Answer:

Media TypeGuidedUnguided
DefinitionPhysical path existsNo physical path
ExamplesTwisted pair, Coax, FiberRadio, Microwave, Satellite
DirectionPoint-to-pointBroadcast

Guided Media:

  • Twisted Pair: Telephone lines, LANs
  • Coaxial Cable: Cable TV, older networks
  • Fiber Optic: High-speed, long-distance

Unguided Media:

  • Radio Waves: WiFi, Bluetooth
  • Microwaves: Point-to-point links
  • Infrared: Short-range communication

Mnemonic: “Guided = Ground, Unguided = Air”

Question 3(b OR) [4 marks]
#

Describe circuit switching and packet switching.

Answer:

FeatureCircuit SwitchingPacket Switching
ConnectionDedicated path establishedNo dedicated path
Resource AllocationFixed bandwidthShared resources
ExampleTraditional telephoneInternet
DelayConstantVariable

Circuit Switching:

  • Setup Phase: Establishes dedicated connection
  • Data Transfer: Continuous transmission
  • Teardown: Releases connection resources

Packet Switching:

  • Store-and-Forward: Packets stored at intermediate nodes
  • Dynamic Routing: Each packet routed independently
  • Resource Sharing: Bandwidth shared among users

Mnemonic: “Circuit = Continuous, Packet = Pieces”

Question 3(c OR) [7 marks]
#

Explain IPv4 OR IPv6 in detail.

Answer (IPv4):

IPv4 Address Structure:

  • 32-bit Address: Divided into 4 octets
  • Dotted Decimal: 192.168.1.1 format
  • Network + Host: Address split into network and host portions
ClassRangeNetwork BitsHost BitsUse
A1-126824Large networks
B128-1911616Medium networks
C192-223248Small networks

Special Addresses:

  • Loopback: 127.0.0.1 (local host)
  • Private: 192.168.x.x, 10.x.x.x, 172.16-31.x.x
  • Broadcast: 255.255.255.255

Subnetting:

  • Subnet Mask: Identifies network portion
  • CIDR: Classless Inter-Domain Routing
  • Variable Length: Different subnet sizes

IPv4 Header:

0VIedTreTsnLDiteoTiSsnof|ot|tiPuiacrrnIlaocaHttetLLioieocAonnodngld1trA6ThFHedylesdpaasregdeseso|rsfFrCSahegermcvekinsctuem32

Mnemonic: “IPv4 = 4 octets, 32 bits, Classes A-C”

Question 4(a) [3 marks]
#

Give full name of ARP and RARP and describe them.

Answer:

Full Names:

  • ARP: Address Resolution Protocol
  • RARP: Reverse Address Resolution Protocol
ProtocolFunction
ARPMaps IP address to MAC address
RARPMaps MAC address to IP address

ARP Process:

  • Request: “Who has IP 192.168.1.1?”
  • Reply: “192.168.1.1 is at MAC 00:1A:2B:3C:4D:5E”
  • Cache: Stores mappings for future use

RARP Process:

  • Diskless Workstations: Get IP from server
  • Broadcast Request: Sends MAC address
  • Server Response: Returns assigned IP address

Mnemonic: “ARP = Address to MAC, RARP = Reverse”

Question 4(b) [4 marks]
#

Describe DSL technology with its advantages and limitations.

Answer:

DSL (Digital Subscriber Line):

TypeSpeedDistance
ADSLUp to 8 Mbps5.5 km
VDSLUp to 52 Mbps1.5 km
SDSLUp to 2 Mbps3 km

Advantages:

  • Existing Infrastructure: Uses telephone lines
  • Always-On: Continuous internet connection
  • Voice + Data: Simultaneous phone and internet
  • Cost-Effective: Affordable for home users

Limitations:

  • Distance Dependent: Speed decreases with distance
  • Upload Speed: Lower than download speed (ADSL)
  • Line Quality: Affected by copper wire condition
  • Availability: Not available in all areas

Mnemonic: “DSL = Digital Subscriber Line”

Question 4(c) [7 marks]
#

Role of DNS- Domain Name System.

Answer:

DNS Functions:

  • Name Resolution: Converts domain names to IP addresses
  • Hierarchical Structure: Organized in tree-like structure
  • Distributed Database: Information stored across multiple servers
graph TD
    A[Root Servers] --> B[Top Level Domain .com]
    A --> C[Top Level Domain .org]
    B --> D[google.com]
    B --> E[yahoo.com]
    D --> F[www.google.com]
    D --> G[mail.google.com]

DNS Hierarchy:

  • Root Domain: Highest level (.)
  • Top-Level Domain: .com, .org, .net, .edu
  • Second-Level Domain: google.com, yahoo.com
  • Subdomain: www.google.com, mail.google.com

DNS Resolution Process:

  1. Client Query: User types www.example.com
  2. Local DNS: Checks local cache
  3. Root Server: Queries root DNS server
  4. TLD Server: Queries .com server
  5. Authoritative Server: Gets IP address
  6. Response: Returns IP to client

DNS Record Types:

  • A Record: Maps domain to IPv4 address
  • AAAA Record: Maps domain to IPv6 address
  • CNAME: Canonical name (alias)
  • MX: Mail exchange server
  • NS: Name server records

Mnemonic: “DNS = Domain Name System”

Question 4(a OR) [3 marks]
#

Give full name of DHCP and BOOTP. and describe them.

Answer:

Full Names:

  • DHCP: Dynamic Host Configuration Protocol
  • BOOTP: Bootstrap Protocol
ProtocolFunction
DHCPAutomatically assigns IP addresses
BOOTPProvides IP address to diskless workstations

DHCP Process:

  • Discover: Client broadcasts request
  • Offer: Server offers IP address
  • Request: Client requests specific IP
  • Acknowledge: Server confirms assignment

BOOTP Process:

  • Static Configuration: Pre-configured IP assignments
  • Diskless Boot: Workstations boot from network
  • Server Response: Provides IP and boot information

Mnemonic: “DHCP = Dynamic, BOOTP = Bootstrap”

Question 4(b OR) [4 marks]
#

Differences Between Virtual Circuits and Datagram Networks.

Answer:

FeatureVirtual CircuitsDatagram Networks
ConnectionConnection-orientedConnectionless
SetupRequires setup phaseNo setup required
RoutingSame path for all packetsIndependent routing
OrderPackets arrive in orderMay arrive out of order
ReliabilityMore reliableLess reliable
OverheadHigher setup overheadLower per-packet overhead

Virtual Circuits:

  • Path Establishment: Creates virtual connection
  • State Information: Maintains connection state
  • Examples: ATM, Frame Relay

Datagram Networks:

  • Independent Packets: Each packet routed separately
  • Stateless: No connection state maintained
  • Examples: Internet Protocol (IP)

Mnemonic: “Virtual = Connection, Datagram = Independent”

Question 4(c OR) [7 marks]
#

Explain TCP and UDP protocol in transport layer

Answer:

FeatureTCPUDP
ConnectionConnection-orientedConnectionless
ReliabilityReliableUnreliable
Header Size20 bytes8 bytes
Flow ControlYesNo
Error ControlYesBasic
SpeedSlowerFaster

TCP (Transmission Control Protocol):

  • Three-Way Handshake: SYN, SYN-ACK, ACK
  • Flow Control: Sliding window mechanism
  • Error Recovery: Retransmission of lost packets
  • Congestion Control: Prevents network overload

TCP Header:

0SHLodeuArnrcckeSneoPqwoulURreetndACcgemPSeNnRS1ut6DmSYebNseuFItrmibnearWtiSiniodznoewPor3t2|

UDP (User Datagram Protocol):

  • Simple Protocol: Minimal overhead
  • Best Effort: No guarantee of delivery
  • Applications: DNS, DHCP, streaming media
  • Real-time Communication: Voice, video applications

UDP Header:

0SourcLeenPgotrht16DestCihneactkisounmPor3t2|

Applications:

  • TCP: Web browsing, email, file transfer
  • UDP: Online gaming, video streaming, DNS queries

Mnemonic: “TCP = Reliable, UDP = Fast”

Question 5(a) [3 marks]
#

Explain any two of following. (1) WWW (2) FTP (3) SMTP

Answer:

WWW (World Wide Web):

  • HTTP Protocol: HyperText Transfer Protocol
  • Web Browser: Client software (Chrome, Firefox)
  • Web Server: Serves web pages (Apache, IIS)

FTP (File Transfer Protocol):

  • File Transfer: Upload and download files
  • Two Modes: Active and passive mode
  • Authentication: Username and password required
ServicePortFunction
WWW80/443Web page delivery
FTP20/21File transfer

Mnemonic: “WWW = Web, FTP = Files”

Question 5(b) [4 marks]
#

Difference between symmetric and asymmetric encryption algorithms.

Answer:

FeatureSymmetricAsymmetric
KeysSame key for encryption/decryptionDifferent keys (public/private)
SpeedFastSlow
Key DistributionDifficultEasy
ExamplesAES, DESRSA, ECC

Symmetric Encryption:

  • Single Key: Same key used by sender and receiver
  • Key Management: Secure key distribution required
  • Performance: Fast encryption/decryption
  • Applications: Bulk data encryption

Asymmetric Encryption:

  • Key Pair: Public key for encryption, private key for decryption
  • Key Distribution: Public key can be shared openly
  • Performance: Slower than symmetric
  • Applications: Digital signatures, key exchange

Mnemonic: “Symmetric = Same, Asymmetric = Different”

Question 5(c) [7 marks]
#

Define the terms “encryption” and “decryption” in the context of cryptography.

Answer:

Encryption:

  • Definition: Process of converting plaintext into ciphertext
  • Purpose: Protect data confidentiality
  • Input: Plaintext + Key
  • Output: Ciphertext

Decryption:

  • Definition: Process of converting ciphertext back to plaintext
  • Purpose: Retrieve original data
  • Input: Ciphertext + Key
  • Output: Plaintext
graph LR
    A[Plaintext] --> B[Encryption]
    B --> C[Ciphertext]
    C --> D[Decryption]
    D --> E[Plaintext]
    F[Key] --> B
    G[Key] --> D

Cryptographic Process:

  1. Sender: Encrypts message using key
  2. Transmission: Sends ciphertext over network
  3. Receiver: Decrypts ciphertext using key
  4. Recovery: Gets original plaintext message

Types of Encryption:

  • Stream Cipher: Encrypts one bit/byte at a time
  • Block Cipher: Encrypts fixed-size blocks
  • Hash Function: One-way encryption (no decryption)

Applications:

  • Data Protection: Secure file storage
  • Communication: Secure messaging
  • Authentication: Digital signatures
  • Privacy: Personal information protection

Security Requirements:

  • Confidentiality: Only authorized users can read
  • Integrity: Data hasn’t been tampered with
  • Authentication: Verify sender identity
  • Non-repudiation: Sender cannot deny sending

Mnemonic: “Encryption = Hide, Decryption = Reveal”

Question 5(a OR) [3 marks]
#

Difference between IMAP and POP3

Answer:

FeatureIMAPPOP3
StorageServer-sideClient-side
AccessMultiple devicesSingle device
OfflineLimitedFull access

IMAP (Internet Message Access Protocol):

  • Server Storage: Messages remain on server
  • Multi-Device: Access from multiple devices
  • Synchronization: Changes sync across devices

POP3 (Post Office Protocol 3):

  • Download: Messages downloaded to client
  • Single Device: Best for one device access
  • Storage: Client manages message storage

Mnemonic: “IMAP = Internet Access, POP3 = Post Office”

Question 5(b OR) [4 marks]
#

Briefly describe the Information Technology (Amendment) Act, 2008, and its impact on cyber laws in India.

Answer:

IT Act 2008 Key Features:

  • Cyber Crimes: Defines various cyber offenses
  • Data Protection: Privacy and security requirements
  • Digital Signatures: Legal recognition of e-signatures
  • Penalties: Fines and imprisonment for violations

Major Amendments:

  • Section 66A: Criminalized offensive messages (later struck down)
  • Section 69: Government power to intercept information
  • Section 72A: Punishment for disclosure of personal information
  • Section 43A: Compensation for data breach

Impact on Cyber Laws:

  • Legal Framework: Comprehensive cyber law structure
  • Business Compliance: Data protection requirements
  • Individual Rights: Privacy protection mechanisms
  • Law Enforcement: Tools for investigating cyber crimes

Mnemonic: “IT Act = Internet Technology Act”

Question 5(c OR) [7 marks]
#

Difference between symmetric and asymmetric encryption algorithms.

Answer:

AspectSymmetric EncryptionAsymmetric Encryption
Key UsageSame key for encrypt/decryptDifferent keys (public/private)
Key ManagementDifficult key distributionEasy key distribution
PerformanceFast processingSlow processing
Key LengthShorter keys (128-256 bits)Longer keys (1024-4096 bits)
ScalabilityPoor (n² key pairs needed)Good (n key pairs needed)
ExamplesAES, DES, 3DES, BlowfishRSA, ECC, DSA, ElGamal

Symmetric Encryption Details:

  • Algorithm Types: Stream ciphers, Block ciphers
  • Key Distribution Problem: Secure channel needed for key exchange
  • Applications: Bulk data encryption, VPNs, file encryption
  • Advantages: Fast, efficient for large amounts of data
  • Disadvantages: Key management complexity, no digital signatures

Asymmetric Encryption Details:

  • Public Key Infrastructure: PKI for key management
  • Digital Signatures: Authentication and non-repudiation
  • Applications: Email security, SSL/TLS, digital certificates
  • Advantages: Secure key exchange, digital signatures
  • Disadvantages: Computationally intensive, slower processing

Hybrid Approach:

  • Best of Both: Combines symmetric and asymmetric encryption
  • Key Exchange: Asymmetric for key distribution
  • Data Encryption: Symmetric for actual data
  • Example: SSL/TLS uses both methods
graph TD
    A[Encryption Methods] --> B[Symmetric]
    A --> C[Asymmetric]
    B --> D[Same Key]
    B --> E[Fast Processing]
    C --> F[Key Pair]
    C --> G[Slow Processing]

Real-world Applications:

  • Banking: ATM transactions use symmetric encryption
  • E-commerce: HTTPS uses hybrid encryption
  • Email: PGP uses asymmetric for key exchange
  • Mobile: WhatsApp uses end-to-end encryption

Security Considerations:

  • Key Length: Longer keys provide better security
  • Algorithm Strength: Choose proven algorithms
  • Implementation: Proper coding prevents vulnerabilities
  • Key Storage: Secure key management essential

Performance Comparison:

OperationSymmetric (AES)Asymmetric (RSA)
Encryption~1000 MB/s~1 MB/s
Key GenerationFastSlow
Memory UsageLowHigh
CPU UsageLowHigh

Future Trends:

  • Quantum Computing: Threat to current asymmetric algorithms
  • Post-Quantum Cryptography: New algorithms being developed
  • Elliptic Curve: More efficient asymmetric encryption
  • Lightweight Cryptography: For IoT devices

Mnemonic: “Symmetric = Same Speed, Asymmetric = Advanced Security”

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