Question 1(a) [3 marks]#
Explain difference between Active and passive network.
Answer:
Active Network | Passive Network |
---|---|
Contains at least one active element (voltage/current source) | Contains only passive elements (R, L, C) |
Can deliver energy to the circuit | Cannot deliver energy to the circuit |
Can amplify signal power | Cannot amplify signal power |
Mnemonic: “Active Adds Power, Passive Parts Take”
Question 1(b) [4 marks]#
State and explain Kirchhoff’s voltage law (KVL).
Answer:
Kirchhoff’s Voltage Law (KVL) states that the algebraic sum of all voltages around any closed loop in a circuit is zero.
Diagram:
graph LR A((A)) -- V1 --> B((B)) B -- V2 --> C((C)) C -- V3 --> D((D)) D -- V4 --> A
Mathematically: V1 + V2 + V3 + V4 = 0
- Voltage drops: When passing through a resistor in direction of current, voltage is negative
- Voltage rises: When passing through a source from negative to positive, voltage is positive
Mnemonic: “Voltage Loop Equals Zero”
Question 1(c) [7 marks]#
Define the following terms: (1) Charge (2) Current (3) Potential (4) E.M.F. (5) Inductance (6) Capacitance (7) Frequency.
Answer:
Term | Definition |
---|---|
Charge | The quantity of electricity measured in coulombs (C) |
Current | The rate of flow of electric charge measured in amperes (A) |
Potential | The electrical pressure or energy per unit charge measured in volts (V) |
E.M.F. | Electromotive Force is the energy supplied by a source per unit charge measured in volts (V) |
Inductance | The property of an electric circuit that opposes change in current, measured in henries (H) |
Capacitance | The ability of a body to store electrical charge, measured in farads (F) |
Frequency | Number of complete cycles per second, measured in hertz (Hz) |
Mnemonic: “Coulombs’ Flow Pressurized by Energy Induces Capacitive Fluctuations”
Question 1(c) OR [7 marks]#
State Ohm’s law. Write its application and limitation.
Answer:
Ohm’s Law states that the current flowing through a conductor is directly proportional to the potential difference and inversely proportional to the resistance.
Diagram:
V = I × R
Where:
- V = Voltage (volts)
- I = Current (amperes)
- R = Resistance (ohms)
Applications:
- Circuit design and analysis
- Power consumption calculations
- Component value determination
- Voltage divider networks
- Current divider networks
Limitations:
- Valid only for linear components
- Not applicable to non-ohmic devices (diodes, transistors)
- Invalid at high temperatures
- Not valid for semiconductors
- Cannot be applied to non-linear resistive elements
Mnemonic: “Volts Reveal Amps’ Motion”
Question 2(a) [3 marks]#
Draw and explain energy band diagrams for insulator, conductor and Semiconductor.
Answer:
Diagram:
graph TD subgraph Conductor A1[Conduction Band] --- B1[Overlapping] B1 --- C1[Valence Band] end subgraph Semiconductor A2[Conduction Band] --- B2[Small Eg] B2 --- C2[Valence Band] end subgraph Insulator A3[Conduction Band] --- B3[Large Eg] B3 --- C3[Valence Band] end
- Conductor: Valence and conduction bands overlap, allowing free electron movement
- Semiconductor: Small energy gap (0.7-3 eV) between bands allows limited conduction
- Insulator: Large energy gap (>3 eV) prevents electrons from moving to conduction band
Mnemonic: “Conductors Overlap, Semiconductors Jump Small, Insulators Block All”
Question 2(b) [4 marks]#
Write statement of Maximum power transfer theorem and reciprocity theorem.
Answer:
Theorem | Statement |
---|---|
Maximum Power Transfer Theorem | Maximum power is transferred from source to load when the load resistance equals the source internal resistance (RL = RS) |
Reciprocity Theorem | In a linear, bilateral network, if voltage source E in branch 1 produces current I in branch 2, then the same voltage source E in branch 2 will produce the same current I in branch 1 |
Mnemonic: “Match Resistance for Maximum Power; Swap Sources, Current Stays”
Question 2(c) [7 marks]#
Explain the formation and conduction of N-type materials.
Answer:
Diagram:
graph TD A[Silicon/Germanium] -- "Add Pentavalent Impurity
(P, As, Sb)" --> B[N-type Semiconductor] B --> C[Extra Electron in Crystal] C --> D[Majority Carriers: Electrons] C --> E[Minority Carriers: Holes]
Formation Process:
- Pure silicon/germanium doped with pentavalent impurity atoms (P, As, Sb)
- Impurity atoms have 5 valence electrons (silicon has 4)
- Four electrons form covalent bonds, fifth becomes free electron
- Creates excess negative charge carriers
Conduction Mechanism:
- Majority carriers: Electrons
- Minority carriers: Holes
- Electron movement provides electrical conduction
- Even at room temperature, free electrons enable current flow
Mnemonic: “Pentavalent Provides Plus-One Electron”
Question 2(a) OR [3 marks]#
Define valence band, conduction band and forbidden gap.
Answer:
Term | Definition |
---|---|
Valence Band | Energy band occupied by valence electrons that are bound to specific atoms in the solid |
Conduction Band | Higher energy band where electrons can move freely throughout the material, enabling electrical conduction |
Forbidden Gap | Energy region between valence and conduction bands where no electron states exist |
Mnemonic: “Valence Binds, Conduction Flows, Forbidden Gaps Block”
Question 2(b) OR [4 marks]#
Define the terms active power, reactive power and power factor with power triangle.
Answer:
Diagram:
- Active Power (P): Actual power consumed, measured in watts (W), P = VI cosθ
- Reactive Power (Q): Power oscillating between source and load, measured in volt-amperes reactive (VAR), Q = VI sinθ
- Power Factor: Ratio of active power to apparent power, PF = cosθ = P/S
Mnemonic: “Real Power Works, Reactive Power Waits”
Question 2(c) OR [7 marks]#
Explain the structure of atom of trivalent, tetravalent and pentavalent elements.
Answer:
Diagram:
graph TD subgraph Trivalent A[3 Valence Electrons] --> B[Examples: B, Al, Ga] end subgraph Tetravalent C[4 Valence Electrons] --> D[Examples: Si, Ge, C] end subgraph Pentavalent E[5 Valence Electrons] --> F[Examples: P, As, Sb] end
Element Type | Structure | Examples | Semiconductor Use |
---|---|---|---|
Trivalent | 3 electrons in outermost shell | B, Al, Ga, In | P-type dopant |
Tetravalent | 4 electrons in outermost shell | Si, Ge, C | Semiconductor base |
Pentavalent | 5 electrons in outermost shell | P, As, Sb | N-type dopant |
Mnemonic: “Three Accepts, Four Forms, Five Donates”
Question 3(a) [3 marks]#
Draw the symbol of photodiode and state its application.
Answer:
Diagram:
Applications of Photodiode:
- Light sensors and detectors
- Optical communication systems
- Solar cells and photovoltaic applications
- Camera exposure controls
- Medical equipment (pulse oximeters)
Mnemonic: “Light Triggers Electric Current”
Question 3(b) [4 marks]#
Write a Short note on LED.
Answer:
Diagram:
- Structure: P-N junction diode that emits light when forward biased
- Working Principle: Electron-hole recombination releases energy as photons
- Types: Various colors based on semiconductor material (GaAs, GaP, GaN)
- Advantages: Low power consumption, long life, small size, fast switching
- Applications: Displays, indicators, lighting, remote controls, optical communications
Mnemonic: “Electrons Jump, Photons Emit”
Question 3(c) [7 marks]#
Draw and explain VI characteristic of PN junction diode.
Answer:
Diagram:
P-N Junction Diode V-I Characteristics:
Forward Bias Region:
- Diode conducts when voltage exceeds knee/cut-in voltage (0.3V for Ge, 0.7V for Si)
- Current increases exponentially with voltage
- Low resistance state
Reverse Bias Region:
- Very small leakage current flows
- Current remains almost constant with increasing reverse voltage
- High resistance state
- Breakdown occurs at high reverse voltage
Key Points:
- Non-linear device
- Unidirectional current flow
- Temperature dependent
Mnemonic: “Forward Flows Freely, Reverse Resists Rigidly”
Question 3(a) OR [3 marks]#
List the applications of PN junction diode.
Answer:
Applications of PN Junction Diode:
- Rectification in power supplies
- Signal demodulation
- Logic gates in digital circuits
- Voltage regulation (with zener diodes)
- Signal clipping and clamping circuits
- Protection circuits against reverse polarity
Mnemonic: “Rectify, Detect, Clip, Protect”
Question 3(b) OR [4 marks]#
Explain the formation of depletion region in unbiased P-N junction.
Answer:
Diagram:
graph LR A[P-type] --- B[Depletion
Region] --- C[N-type] D[+] --- B --- E[-]
Formation Process:
- Electrons from N-side diffuse into P-side
- Holes from P-side diffuse into N-side
- Recombination occurs at junction
- Immobile ions remain (positive in N-side, negative in P-side)
- Electric field develops, opposing further diffusion
- Equilibrium is established, creating depletion region
Characteristics:
- Free of charge carriers
- Acts as insulator/barrier
- Creates built-in potential
Mnemonic: “Diffusion Creates Barrier Field”
Question 3(c) OR [7 marks]#
Explain construction, working and applications of PN junction diode.
Answer:
Diagram:
graph LR A[P-type] --- B[Junction] --- C[N-type] D[Anode] --- A C --- E[Cathode]
Construction:
- P-type semiconductor joined with N-type semiconductor
- Made from single crystal of silicon or germanium
- Metal contacts connected to P and N regions
Working:
Forward Bias:
- Positive to P, negative to N
- Depletion region narrows
- Current flows when voltage exceeds barrier potential
Reverse Bias:
- Positive to N, negative to P
- Depletion region widens
- Only small leakage current flows
Applications:
- Power rectification
- Signal detection
- Voltage regulation
- Switching applications
- Protection circuits
- Logic gates
Mnemonic: “Join P-N, Control Current Direction”
Question 4(a) [3 marks]#
Define: (1) Ripple frequency (2) Ripple factor (3) PIV of a diode.
Answer:
Term | Definition |
---|---|
Ripple Frequency | Frequency of the AC component remaining in the rectified DC output (2× input frequency for full-wave, 1× for half-wave) |
Ripple Factor | Ratio of RMS value of AC component to the DC component in rectifier output (γ = Vac(rms)/Vdc) |
PIV of a diode | Peak Inverse Voltage is the maximum reverse voltage a diode can withstand without breakdown |
Mnemonic: “Frequency Fluctuates, Factor Measures, PIV Protects”
Question 4(b) [4 marks]#
Give comparison between full wave rectifier with two diodes and full wave bridge rectifier.
Answer:
Parameter | Center-Tapped Full Wave | Bridge Rectifier |
---|---|---|
Number of Diodes | 2 | 4 |
Transformer | Center-tapped required | Simple transformer |
PIV | 2Vm | Vm |
Efficiency | 81.2% | 81.2% |
Ripple Factor | 0.48 | 0.48 |
Output | Vm/π | 2Vm/π |
Cost | Higher transformer cost | Higher diode cost |
Mnemonic: “Two Diodes Tap Center, Four Make Bridge”
Question 4(c) [7 marks]#
Explain zener diode as voltage regulator.
Answer:
Diagram:
Working Principle:
- Zener diode operates in reverse breakdown region
- Maintains constant voltage across its terminals
- Acts as voltage reference
Circuit Operation:
- Series resistor Rs limits current
- Zener conducts when input exceeds breakdown voltage
- Excess current flows through zener diode
- Output voltage remains constant at zener voltage
Advantages:
- Simple circuit
- Low cost
- Good regulation for small load changes
Limitations:
- Power dissipation in zener and series resistor
- Limited current capability
- Temperature dependency
Mnemonic: “Zener Breaks Down to Hold Voltage Steady”
Question 4(a) OR [3 marks]#
What is rectifier? Explain full wave rectifier with waveforms.
Answer:
Rectifier: A circuit that converts AC voltage to pulsating DC voltage.
Diagram:
Waveforms:
Mnemonic: “Both Half-Cycles Become Positive”
Question 4(b) OR [4 marks]#
Why filter is required in rectifier? State the different types of filter and explain any one type of filter.
Answer:
Need for Filter:
- Rectifier output contains AC ripple component
- Pure DC required for electronic circuits
- Filters smooth pulsating DC by removing AC components
Types of Filters:
- Capacitor filter (C-filter)
- Inductor filter (L-filter)
- LC filter
- π (Pi) filter
- CLC filter
Capacitor Filter:
graph LR A[AC Input] --> B[Rectifier] --> C[Capacitor Filter] --> D[DC Output]
Working:
- Capacitor charges during voltage rise
- Discharges slowly during voltage fall
- Provides current when input decreases
- Reduces ripple voltage
Advantages:
- Simple and inexpensive
- Effective for light loads
- Reduces ripple significantly
Mnemonic: “Capacitor Catches Peaks, Releases Slowly”
Question 4(c) OR [7 marks]#
Write the need of rectifier. Explain bridge rectifier with circuit diagram and draw its input and output waveforms.
Answer:
Need of Rectifier:
- Convert AC to DC for electronic devices
- Most electronic circuits require DC power
- Batteries provide DC but AC is distributed
- Building block of power supplies
- Essential for charging systems
Bridge Rectifier Circuit:
Input Waveform:
Output Waveform:
Working:
- During positive half cycle: D1 and D4 conduct
- During negative half cycle: D2 and D3 conduct
- Load receives unidirectional current in both cycles
- Utilizes both halves of input waveform
Mnemonic: “Four Diodes Direct All Current One Way”
Question 5(a) [3 marks]#
Explain causes of electronic waste.
Answer:
Causes of Electronic Waste:
- Rapid technological advancement
- Planned obsolescence of products
- Decreasing product lifespan
- Consumer behavior preferring new devices
- Limited repair options for electronics
- High repair costs compared to replacement
Mnemonic: “Technology Advances, Products Expire Rapidly”
Question 5(b) [4 marks]#
Compare PNP and NPN transistors.
Answer:
Parameter | PNP Transistor | NPN Transistor |
---|---|---|
Symbol | ![]() | ![]() |
Majority Carriers | Holes | Electrons |
Current Flow | Emitter to Collector | Collector to Emitter |
Biasing | Emitter more positive than Base | Base more positive than Emitter |
Switching Speed | Slower | Faster |
Applications | Low frequency, high current | High frequency, switching |
Diagram:
Mnemonic: “Negative-Positive-Negative vs Positive-Negative-Positive”
Question 5(c) [7 marks]#
Draw the symbol, explain the construction and working of MOSFET.
Answer:
Symbol:
Construction:
graph TD A[Metal Gate] --- B[Silicon Dioxide Insulator] B --- C[N-type Channel] C --- D[P-type Substrate] E[Source] --- C C --- F[Drain]
Working Principle:
Enhancement Mode N-Channel MOSFET:
- No channel exists without gate voltage
- Positive gate voltage attracts electrons from substrate
- Induced channel allows current flow from drain to source
- Increasing gate voltage enhances conductivity
Key Features:
- Voltage-controlled device (high input impedance)
- No gate current required (unlike BJT)
- Faster switching than BJT
- Lower power dissipation
Applications:
- Digital logic circuits
- Switching applications
- Amplifiers
- Power control devices
Mnemonic: “Gate Voltage Creates Electron Channel”
Question 5(a) OR [3 marks]#
Explain methods to handle electronic waste.
Answer:
Methods to Handle Electronic Waste:
Method | Description |
---|---|
Reduce | Designing longer-lasting electronics, modular design for upgrading |
Reuse | Donating or selling functional devices, repurposing components |
Recycle | Proper dismantling and material recovery (precious metals, plastics) |
Regulation | E-waste management policies, extended producer responsibility |
Recovery | Extracting valuable materials through specialized processes |
Mnemonic: “Reduce, Reuse, Recycle, Regulate, Recover”
Question 5(b) OR [4 marks]#
Derive the relationship between αdc and βdc.
Answer:
Diagram:
Transistor Current Relationships:
- IE = IC + IB (Current entering equals current leaving)
- αdc = IC/IE (Common Base current gain)
- βdc = IC/IB (Common Emitter current gain)
Derivation:
- From IE = IC + IB
- Divide both sides by IC: IE/IC = 1 + IB/IC
- Therefore: 1/αdc = 1 + 1/βdc
- Solving for βdc: βdc = αdc/(1-αdc)
- And for αdc: αdc = βdc/(1+βdc)
Table of Values:
αdc | βdc |
---|---|
0.9 | 9 |
0.95 | 19 |
0.99 | 99 |
Mnemonic: “Alpha-Beta Relate as αdc = βdc/(1+βdc)”
Question 5(c) OR [7 marks]#
Explain common collector configuration with its input and output characteristics.
Answer:
Common Collector Circuit (Emitter Follower):
Input Characteristics: (IB vs VBE)
Output Characteristics: (IE vs VCE)
Key Features:
- Voltage gain ≈ 1 (slightly less)
- High current gain (β+1)
- High input impedance
- Low output impedance
- No phase inversion between input and output
- Used as buffer/impedance matching circuit
Mnemonic: “Emitter Follows Base Voltage”