Skip to main content
  1. Resources/
  2. Study Materials/
  3. Information & Communication Technology Engineering/
  4. ICT Semester 2/
  5. Electronics Devices & Circuits (1323202)/

Electronics Devices & Circuits (1323202) - Summer 2024 Solution

13 mins· ·
Study-Material Solutions Electronics 1323202 2024 Summer
Milav Dabgar
Author
Milav Dabgar
Experienced lecturer in the electrical and electronic manufacturing industry. Skilled in Embedded Systems, Image Processing, Data Science, MATLAB, Python, STM32. Strong education professional with a Master’s degree in Communication Systems Engineering from L.D. College of Engineering - Ahmedabad.
Table of Contents

Question 1(a) [3 marks]
#

What is heat sink. lists its types

Answer: A heat sink is a passive device that absorbs and dissipates heat from electronic components to prevent overheating.

Table: Types of Heat Sinks

TypeDescription
PassiveUses natural convection without external power
ActiveIncorporates fans or liquid cooling
RadialFins arranged in radial pattern from center
Pin-finUses pins or rods for increased surface area
ExtrudedMade by forcing aluminum through shaped die

Mnemonic: “PAPER” (Passive, Active, Pin-fin, Extruded, Radial)

Question 1(b) [4 marks]
#

Define the Following: 1. Thermal Runaway 2. Thermal Stability

Answer:

Thermal Runaway: The self-accelerating destructive process where increased temperature causes increased current flow, which further increases temperature, potentially destroying the transistor.

Thermal Stability: The ability of a transistor circuit to maintain stable operation despite temperature changes, preventing thermal runaway.

Diagram: Thermal Runaway Process

graph LR
    A[Temperature Rises] --> B[Collector Current Increases]
    B --> C[Power Dissipation Increases]
    C --> A
    A --> D[Device Destruction]

Mnemonic: “RISE” (Runaway Is Self-Escalating)

Question 1(c) [7 marks]
#

Explain voltage divider bias in details.

Answer: Voltage divider bias is a common transistor biasing technique that provides stable operation.

Circuit Diagram:

graph LR
    VCC["+VCC"] --- R1[R1]
    R1 --- B[Base]
    B --- R2[R2]
    R2 --- GND[Ground]
    B --- BC[Transistor]
    BC --- E[Emitter]
    BC --- C[Collector]
    C --- RC[RC]
    RC --- VCC
    E --- RE[RE]
    RE --- GND
  • Voltage divider network: R1 and R2 establish a fixed base voltage
  • Stable Q-point: Maintains operating point despite temperature variations
  • Better stability: Higher stability factor compared to fixed bias
  • Self-adjusting: Base current automatically adjusts to counter temperature changes

Mnemonic: “VSST” (Voltage divider, Stable, Self-adjusting, Temperature resistant)

Question 1(c) OR [7 marks]
#

Explain D.C. Load Line in details.

Answer: DC Load Line is a graphical method for analyzing transistor bias conditions.

Diagram: DC Load Line on Transistor Characteristic Curves

graph LR
    A[IC = VCC/RC at VCE = 0] --- B[Q-point]
    B --- C[VCE = VCC at IC = 0]
    
    classDef default fill:#f9f,stroke:#333,stroke-width:2px;
    class A,B,C default
  • Definition: Graphical line showing all possible operating points for a given circuit
  • Endpoints: (0, VCC/RC) and (VCC, 0) on IC-VCE plane
  • Q-point: Intersection of load line with transistor characteristic curve
  • Equation: IC = (VCC - VCE)/RC

Mnemonic: “QECC” (Q-point Exists where Collector Current meets characteristics)

Question 2(a) [3 marks]
#

Explain how transistor works as a switch.

Answer: A transistor switch operates in either saturation (ON) or cutoff (OFF) regions.

Table: Transistor Switch Operation

StateRegionBase CurrentCollector CurrentVCE
OFFCutoffIB ≈ 0IC ≈ 0VCE ≈ VCC
ONSaturationIB > IB(sat)IC ≈ IC(sat)VCE ≈ 0.2V

Mnemonic: “COS” (Cutoff Off, Saturation on)

Question 2(b) [4 marks]
#

Draw and explain colpitt oscillator.

Answer: Colpitt oscillator is an LC oscillator using a capacitive voltage divider for feedback.

Circuit Diagram:

graph LR
    Q[Transistor] --- L[Inductor]
    L --- C1[C1]
    C1 --- C2[C2]
    C2 --- Q
    Q --- RE[RE]
    RE --- GND[Ground]
    Q --- RC[RC]
    RC --- VCC[+VCC]
  • Feedback: Provided by capacitive voltage divider (C1, C2)
  • Resonant frequency: f = 1/(2π√(L×C)), where C = (C1×C2)/(C1+C2)
  • Oscillation: Maintains through regenerative feedback
  • Phase shift: 360° around the loop

Mnemonic: “CFPO” (Capacitive Feedback Produces Oscillations)

Question 2(c) [7 marks]
#

Explain Frequency Response Two Stage RC Coupled Amplifier with circuit diagram.

Answer: Two-stage RC coupled amplifier combines two amplifier stages with RC coupling.

Circuit Diagram:

graph LR
    VIN[Input] --- C1[C1]
    C1 --- B1[Base1]
    B1 --- Q1[Transistor1]
    Q1 --- E1[Emitter1]
    E1 --- GND[Ground]
    Q1 --- C2[Collector1]
    C2 --- RC1[RC1]
    RC1 --- VCC[+VCC]
    C2 --- CC[Coupling Capacitor]
    CC --- B2[Base2]
    B2 --- Q2[Transistor2]
    Q2 --- E2[Emitter2]
    E2 --- GND
    Q2 --- C3[Collector2]
    C3 --- RC2[RC2]
    RC2 --- VCC
    C3 --- COUT[Output Capacitor]
    COUT --- VOUT[Output]

Frequency Response:

graph LR
    A[Low Frequency Drop] --- B[Mid Frequency Flat]
    B --- C[High Frequency Drop]
    
    classDef default fill:#f9f,stroke:#333,stroke-width:2px;
    class A,B,C default
  • Low frequency: Gain drops due to coupling capacitor impedance
  • Mid frequency: Maximum flat gain region (bandwidth)
  • High frequency: Gain drops due to transistor capacitance effects
  • Overall gain: Product of individual stage gains

Mnemonic: “LMH” (Low drops, Mid flat, High drops)

Question 2(a) OR [3 marks]
#

Draw circuit diagram of Hartley oscillator.

Answer:

Circuit Diagram of Hartley Oscillator:

graph TD
    Q[Transistor] --- L1[L1]
    L1 --- L2[L2]
    L2 --- C[Capacitor]
    C --- Q
    Q --- RE[RE]
    RE --- GND[Ground]
    Q --- RC[RC]
    RC --- VCC[+VCC]

Mnemonic: “ITLC” (Inductor Tapped for LC Circuit)

Question 2(b) OR [4 marks]
#

List different types of negative feedback.

Answer:

Table: Types of Negative Feedback

TypeConfigurationEffect on Parameters
Voltage SeriesOutput voltage fed to input in seriesIncreases input impedance, reduces distortion
Voltage ShuntOutput voltage fed to input in parallelDecreases input impedance, increases bandwidth
Current SeriesOutput current fed to input in seriesIncreases output impedance, stabilizes current gain
Current ShuntOutput current fed to input in parallelDecreases output impedance, stabilizes voltage gain

Mnemonic: “VSCS” (Voltage Series, Current Shunt)

Question 2(c) OR [7 marks]
#

List advantages of Negative feedback amplifier and Explain voltage series negative feedback in details.

Answer:

Advantages of Negative Feedback:

  • Stabilizes gain against component variations
  • Reduces distortion and noise
  • Increases bandwidth
  • Modifies input/output impedance
  • Improves linearity

Voltage Series Negative Feedback:

graph LR
    VIN[Input] --- SUM[Summing Point]
    SUM --- A[Amplifier A]
    A --- VOUT[Output]
    VOUT --- FB[Feedback Network β]
    FB --- SUM
  • Configuration: Output voltage sampled, fed back in series with input
  • Closed-loop gain: ACL = A/(1+Aβ), where A is open-loop gain and β is feedback fraction
  • Input impedance: Increases by factor (1+Aβ)
  • Output impedance: Decreases by factor (1+Aβ)

Mnemonic: “SIGO” (Stable gain, Increased input impedance, Gain reduction, Output impedance reduction)

Question 3(a) [3 marks]
#

Draw circuit of SCR using two transistor analogy.

Answer:

Two Transistor Analogy of SCR:

graph LR
    A[Anode] --- C1[Collector PNP]
    C1 --- E2[Emitter NPN]
    E2 --- K[Cathode]
    E1[Emitter PNP] --- B2[Base NPN]
    B1[Base PNP] --- C2[Collector NPN]
    G[Gate] --- B1

Mnemonic: “PNPNPN” (PNP and NPN structure)

Question 3(b) [4 marks]
#

Draw and explain Natural Commutation of SCR.

Answer: Natural commutation occurs when the SCR current naturally falls below the holding current.

Circuit Diagram:

graph LR
    AC[AC Source] --- SCR[SCR]
    SCR --- LOAD[Load]
    LOAD --- AC

Current Waveform:

       ┌───┐     ┌───┐
       │   │     │   │
───────┘   └─────┘   └─────
  SCR OFF    SCR OFF
       SCR ON    SCR ON
  • Definition: SCR turns off automatically when current falls below holding current
  • AC circuit: Occurs naturally at end of each positive half-cycle
  • Zero crossing: SCR turns off when AC voltage crosses zero
  • No external circuit: No additional components needed for turn-off

Mnemonic: “NAZC” (Natural At Zero Crossing)

Question 3(c) [7 marks]
#

Explain how TRIAC can be used as fan regulator and on-off control for ac power.

Answer: TRIAC is a bidirectional device ideal for AC power control applications.

TRIAC Fan Regulator Circuit:

graph LR
    AC[AC Source] --- TRIAC[TRIAC]
    TRIAC --- FAN[Fan Motor]
    FAN --- AC
    DIAC[DIAC] --- G[Gate]
    R[R] --- DIAC
    C[C] --- R
    TRIAC --- G
    P[Potentiometer] --- R
    AC --- P

TRIAC On-Off Control:

graph LR
    AC[AC Source] --- TRIAC[TRIAC]
    TRIAC --- LOAD[AC Load]
    LOAD --- AC
    SWITCH[Switch] --- G[Gate]
    R[Resistor] --- SWITCH
    AC --- R
    TRIAC --- G
  • Fan Regulation: Phase control technique varies power to fan
  • Potentiometer: Adjusts firing angle of TRIAC
  • On-Off Control: Simple switch triggers TRIAC gate
  • Bidirectional: Controls current in both half-cycles

Mnemonic: “FPOB” (Fan Power is controlled by Phase angle in both directions)

Question 3(a) OR [3 marks]
#

Draw symbol of SCR, DIAC and TRIAC.

Answer:

Symbols of Thyristors:

SAGKCR|DIACTGRIAC

Mnemonic: “SDT” (SCR has gate on one side, DIAC has none, TRIAC has gate in middle)

Question 3(b) OR [4 marks]
#

Draw and explain Gate triggering of SCR.

Answer: Gate triggering is the most common method to turn on an SCR.

Circuit Diagram:

graph LR
    AC[AC Source] --- SCR[SCR]
    SCR --- LOAD[Load]
    LOAD --- AC
    R[Resistor] --- G[Gate]
    SW[Switch] --- R
    BAT[Battery] --- SW
    G --- SCR
    BAT --- LOAD
  • Principle: Applying positive voltage between gate and cathode
  • Current requirement: Small gate current triggers much larger anode current
  • Latching: Once triggered, SCR remains ON even if gate signal is removed
  • Turn-off: Requires reducing anode current below holding current

Mnemonic: “GPLT” (Gate Pulse Latches Thyristor)

Question 3(c) OR [7 marks]
#

Draw Construction and Voltage Vs Current characteristic of SCR and explain V-I characteristic.

Answer: SCR (Silicon Controlled Rectifier) is a four-layer PNPN semiconductor device.

SCR Construction:

graph LR
    A[Anode] --- P1[P-layer]
    P1 --- N1[N-layer]
    N1 --- P2[P-layer]
    P2 --- N2[N-layer]
    N2 --- K[Cathode]
    G[Gate] --- P2

V-I Characteristic:

          I
          ↑
          │        ON State
          │       ┌────────
          │       │
          │       │
  Holding │       │
  current ├───────┤
          │       │
          │Forward│
          │breakover
          │voltage│
          │       │
          └───────┴──────→ V
                   Reverse
                   breakdown
                   voltage
  • Forward blocking region: SCR conducts minimal current until breakover voltage
  • Forward conduction region: Low resistance state after triggering
  • Reverse blocking region: Blocks current in reverse direction
  • Gate triggering: Reduces breakover voltage, facilitating turn-on

Mnemonic: “FBRH” (Forward Blocking, Reverse blocking, Holding current)

Question 4(a) [3 marks]
#

Explain OP-AMP as a summing amplifier.

Answer: Summing amplifier adds multiple input signals with weighted gains.

Circuit Diagram:

graph LR
    V1[V1] --- R1[R1] --- N["\-"]
    V2[V2] --- R2[R2] --- N
    V3[V3] --- R3[R3] --- N
    P["\+"] --- GND[Ground]
    N --- A[Op-Amp] --- Vout[Vout]
    A --- Rf[Rf]
    Rf --- N
  • Function: Outputs weighted sum of input voltages
  • Output equation: Vout = -(V1×Rf/R1 + V2×Rf/R2 + V3×Rf/R3)
  • Equal weights: When R1 = R2 = R3, output is simple sum multiplied by -Rf/R
  • Virtual ground: Inverting input maintains 0V potential

Mnemonic: “SWAP” (Sum Weighted And Proportional)

Question 4(b) [4 marks]
#

Define the following OP-AMP parameters: 1. input bias current 2. CMRR

Answer:

Input Bias Current: The average of the currents flowing into the two input terminals of an op-amp when the output is at zero.

CMRR (Common Mode Rejection Ratio): The ratio of differential gain to common-mode gain, indicating how well an op-amp rejects signals common to both inputs.

Table: Op-Amp Parameters

ParameterTypical ValueImportance
Input Bias Current20-200 nALower is better for high impedance circuits
CMRR80-120 dBHigher is better for noise rejection

Mnemonic: “BIC-CMR” (Bias Is Current, Common Mode Rejection)

Question 4(c) [7 marks]
#

Draw and explain monostable multivibrator using 555 Timer.

Answer: Monostable multivibrator generates a single pulse of predetermined duration when triggered.

Circuit Diagram:

graph TD
    VCC[+VCC] --- R[R]
    R --- DIS[DIS]
    DIS --- THR[THR]
    THR --- C[C]
    C --- GND[Ground]
    VCC --- RST[RST]
    VCC --- VCC1[VCC]
    TRG[TRIG] --- C
    IC[555 Timer] --- TRG
    IC --- THR
    IC --- RST
    IC --- VCC1
    IC --- GND1[GND]
    IC --- DIS
    IC --- OUT[OUTPUT]
    GND1 --- GND
    OUT --- OUTPUT[Output]

Output Waveform:

Trigger  ___┐      ____________
             │______│
             
Output   ____┌──────┐__________
              │      │
              T = 1.1RC
  • Operation: Single stable state (output LOW), temporarily HIGH when triggered
  • Pulse width: T = 1.1 × R × C (seconds)
  • Triggering: Falling edge on TRIG pin (pin 2)
  • Timing components: R and C determine pulse duration

Mnemonic: “POST” (Pulse Output, Single Trigger)

Question 4(a) OR [3 marks]
#

Draw the circuit diagram of OP-AMP as a inverting amplifier.

Answer:

Inverting Amplifier Circuit:

graph LR
    VIN[Input] --- R1[R1] --- N["\-"]
    P["\+"] --- GND[Ground]
    N --- A[Op-Amp] --- VOUT[Output]
    A --- RF[Rf]
    RF --- N

Mnemonic: “IRON” (Inverting Requires One Negative input)

Question 4(b) OR [4 marks]
#

Define the following OP-AMP parameters: 1. input offset current 2. slew rate

Answer:

Input Offset Current: The difference between the currents flowing into the two input terminals of an op-amp.

Slew Rate: The maximum rate of change of output voltage per unit of time, typically measured in V/μs.

Table: Op-Amp Parameters

ParameterTypical ValueImportance
Input Offset Current2-50 nALower is better for precision applications
Slew Rate0.5-20 V/μsHigher is better for high-frequency operation

Mnemonic: “IOSR” (Input Offset and Slew Rate)

Question 4(c) OR [7 marks]
#

Explain op-amp as Inverting amplifier and obtain equation of its Voltage gain.

Answer: Inverting amplifier produces an output signal that is inverted and amplified.

Circuit Diagram:

graph LR
    VIN[Input] --- R1[R1] --- N["\-"]
    P["\+"] --- GND[Ground]
    N --- A[Op-Amp] --- VOUT[Output]
    A --- RF[Rf]
    RF --- N

Voltage Gain Derivation:

At node N (inverting input):
I1 + If = 0  (By Kirchhoff's Current Law)
(Vin - VN)/R1 + (Vout - VN)/Rf = 0

Since VN ≈ 0 (virtual ground):
Vin/R1 + Vout/Rf = 0
Vout/Vin = -Rf/R1
  • Gain equation: Vout/Vin = -Rf/R1
  • Virtual ground: Inverting terminal maintained at 0V
  • Input impedance: Equal to R1
  • Negative feedback: Provides stability and linearity

Mnemonic: “GIVN” (Gain Is Negative, Virtual ground)

Question 5(a) [3 marks]
#

Draw the block diagram of IC 555.

Answer:

Block Diagram of IC 555:

graph LR
    VCC[VCC] --- RS[R-S FF]
    GND[GND] --- CS[Comparators]
    THR[Threshold] --- CS
    TRG[Trigger] --- CS
    CS --- RS
    RS --- O[Output Stage]
    O --- OUT[Output]
    RS --- DR[Discharge]
    RST[Reset] --- RS
    VCC --- VD[Voltage Divider]
    VD --- CS
    CTRL[Control] --- VD

Mnemonic: “CVOT” (Comparators, Voltage divider, Output stage, Timer)

Question 5(b) [4 marks]
#

Draw the circuit diagram of OP-AMP as a wein bridge oscillator.

Answer:

Wein Bridge Oscillator Circuit:

graph TD
    A[Op-Amp] --- P["+"]
    A --- N["-"]
    P --- R1[R]
    R1 --- C1[C]
    C1 --- GND[Ground]
    P --- R2[R]
    R2 --- C2[C in parallel with R]
    C2 --- GND
    N --- R3[R3]
    R3 --- GND
    N --- R4[R4]
    R4 --- O[Output]
    A --- O

Mnemonic: “WPRC” (Wein Produces Resonant Circuit)

Question 5(c) [7 marks]
#

Explain working of different types of Fixed and variable voltage regulator IC.

Answer: Voltage regulator ICs maintain stable output voltage despite input or load variations.

Fixed Voltage Regulators:

graph LR
    VIN[Input] --- IC[78XX/79XX] --- VOUT[Output]
    IC --- GND[Ground]
    C1[Input Cap] --- VIN
    C1 --- GND
    C2[Output Cap] --- VOUT
    C2 --- GND

Variable Voltage Regulator:

graph TD
    VIN[Input] --- IC[LM317]
    IC --- VOUT[Output]
    IC --- ADJ[Adjust]
    R1[R1] --- ADJ
    R1 --- VOUT
    R2[R2] --- ADJ
    R2 --- GND[Ground]
    C1[Input Cap] --- VIN
    C1 --- GND
    C2[Output Cap] --- VOUT
    C2 --- GND
  • Fixed regulators: 78XX (positive) and 79XX (negative) series provide specific voltages
  • Variable regulators: LM317 (positive) and LM337 (negative) allow adjustable output
  • Three-terminal design: Input, output, and ground/adjust terminals
  • Output equation for LM317: Vout = 1.25V × (1 + R2/R1)
  • Protection features: Short circuit, thermal overload, and safe area protection

Mnemonic: “FAVOR” (Fixed And Variable Output Regulators)

Question 5(a) OR [3 marks]
#

Draw the block diagram of astable multivibrator using 555 timer.

Answer:

Astable Multivibrator Block Diagram:

graph LR
    VCC[VCC] --- R1[R1] --- R2[R2]
    R2 --- DIS[Discharge]
    DIS --- THR[Threshold]
    THR --- C[Capacitor]
    C --- GND[Ground]
    TRG[Trigger] --- THR
    RESET[Reset] --- VCC
    IC[555 Timer] --- THR
    IC --- TRG
    IC --- DIS
    IC --- RESET
    IC --- OUT[Output]
    IC --- VCC1[VCC]
    IC --- GND1[GND]
    VCC1 --- VCC
    GND1 --- GND

Mnemonic: “FOFT” (Free-running Oscillator From Timer)

Question 5(b) OR [4 marks]
#

Draw and explain solar based battery charger circuits.

Answer: Solar battery charger converts solar energy to charge batteries.

Circuit Diagram:

graph LR
    SP[Solar Panel] --- D[Blocking Diode]
    D --- R[Regulator IC]
    R --- B[Battery]
    R --- LED[Charge Indicator]
    LED --- GND[Ground]
    B --- GND
  • Solar panel: Converts sunlight to DC electricity
  • Blocking diode: Prevents battery discharge through panel at night
  • Regulator IC: Controls charging voltage and current
  • Charge indicator: Shows charging status
  • Protection: Overcharge and reverse polarity protection

Mnemonic: “SBRCP” (Solar, Blocking diode, Regulator, Charging, Protection)

Question 5(c) OR [7 marks]
#

Draw and explain the block diagram of SMPS.

Answer: SMPS (Switch Mode Power Supply) converts electrical power efficiently using switching regulators.

Block Diagram:

graph LR
    AC[AC Input] --- EMI[EMI Filter]
    EMI --- REC[Rectifier]
    REC --- C[Input Filter]
    C --- SW[Switching Circuit]
    SW --- TR[Transformer]
    TR --- OR[Output Rectifier]
    OR --- OF[Output Filter]
    OF --- O[DC Output]
    FB[Feedback] --- O
    FB --- CTRL[Control Circuit]
    CTRL --- SW
  • EMI filter: Removes noise from AC input
  • Rectifier: Converts AC to unregulated DC
  • Switching circuit: Chops DC at high frequency (20-100 kHz)
  • Transformer: Provides isolation and voltage conversion
  • Output rectifier: Converts high-frequency AC back to DC
  • Output filter: Smooths DC output
  • Feedback circuit: Monitors output for regulation
  • Control circuit: Adjusts switching based on feedback

Mnemonic: “ERST-FOFC” (EMI filter, Rectifier, Switching, Transformer, Feedback, Output rectifier, Filter, Control)

Related

Electronics Devices & Circuits (1323202) - Winter 2024 Solution
14 mins
Study-Material Solutions Electronics 1323202 2024 Winter
Electronics Devices & Circuits (1323202) - Summer 2023 Solution
13 mins
Study-Material Solutions Electronics 1323202 2023 Summer
Advanced Python Programming (4321602) - Summer 2024 Solution
17 mins
Study-Material Solutions Python 4321602 2024 Summer
Consumer Electronics & Maintenance (4341107) - Summer 2024 Solution
15 mins
Study-Material Solutions Consumer-Electronics 4341107 2024 Summer
Embedded System (4343204) - Summer 2024 Solution
16 mins
Study-Material Solutions Embedded-System 4343204 2024 Summer
Digital Electronics (4321102) - Summer 2024 Solution
16 mins
Study-Material Solutions Digital-Electronics 4321102 2024 Summer