Skip to main content
  1. Resources/
  2. Study Materials/
  3. Information & Communication Technology Engineering/
  4. ICT Semester 2/

Electronics Devices & Circuits (1323202) - Winter 2023 Solution

14 mins· ·
Study-Material Solutions Electronics 1323202 2023 Winter
Milav Dabgar
Author
Milav Dabgar
Experienced lecturer in the electrical and electronic manufacturing industry. Skilled in Embedded Systems, Image Processing, Data Science, MATLAB, Python, STM32. Strong education professional with a Master’s degree in Communication Systems Engineering from L.D. College of Engineering - Ahmedabad.
Table of Contents

Question 1(a) [3 marks]
#

Explain the concept of dc load line with the help of neat diagram.

Answer: DC load line is a straight line on output characteristics that shows all possible operating points of a transistor.

Diagram:

graph LR
    style O fill:#fff,stroke:#000
    style Vcesat fill:#fff,stroke:#000
    style Icsat fill:#fff,stroke:#000
    style Vcc fill:#fff,stroke:#000
    O((O)) --- Icsat((Icsat))
    O --- Vcc((Vcc))
    Icsat --- Vcesat((Vcesat))
    Vcesat --- Vcc

  • Collector saturation current: When VCE = 0, IC = VCC/RC
  • Cutoff voltage: When IC = 0, VCE = VCC
  • Q-point: Operating point along load line

Mnemonic: “LEVEL” - “Load line Establishes Voltage and current for Every Load condition”

Question 1(b) [4 marks]
#

Explain thermal runaway in detail.

Answer: Thermal runaway is a condition where heat causes transistor’s collector current to increase, which generates more heat, leading to destruction.

Diagram:

flowchart LR
    A[Temperature Increases] --> B[Leakage Current Increases]
    B --> C[Collector Current Increases]
    C --> D[More Power Dissipation]
    D --> E[Further Temperature Rise]
    E --> A

  • Heat generation: Power dissipation = VCE × IC
  • Critical effect: Increased junction temperature decreases VBE
  • Prevention: Heat sinks, thermal stabilization circuits, proper biasing
  • Danger: Can destroy transistor if not controlled

Mnemonic: “HEAT” - “Higher Emission Amplifies Temperature”

Question 1(c) [7 marks]
#

Draw the circuit diagram and frequency response of a two stage R-C coupled amplifier. Explain the importance of each component.

Answer: R-C coupled amplifier uses capacitors to connect multiple transistor stages for higher gain.

Diagram:

VinQR11C1C2R3QRR224Vout

Frequency Response:

xychart-beta
    title "Frequency Response"
    x-axis [10Hz, 100Hz, 1kHz, 10kHz, 100kHz, 1MHz]
    y-axis "Gain(dB)" 0 --> 40
    line [10, 30, 40, 40, 30, 10]
    annotations
        600Hz "Low frequency cutoff"
        50kHz "High frequency cutoff"

  • Coupling capacitors: Block DC, allow AC signal transfer between stages
  • Biasing resistors: Establish proper Q-point for transistor operation
  • Bypass capacitors: Prevent gain reduction from negative feedback
  • Bandwidth: Range between low and high cutoff frequencies

Mnemonic: “CARS” - “Coupling capacitors Allow Resistance Separation”

OR
#

Question 1(c) [7 marks]
#

Compare negative and positive feedback in amplifier.

Answer: Feedback systems return a portion of output to the input with different effects based on polarity.

Table:

ParameterNegative FeedbackPositive Feedback
GainDecreasesIncreases
BandwidthIncreasesDecreases
StabilityImprovesDecreases
DistortionReducesIncreases
NoiseReducesAmplifies
Input/Output impedanceCan be controlledUnpredictable
ApplicationsAmplifiers, regulatorsOscillators, Schmitt triggers
  • Negative feedback: Output is out of phase with input (180° shifted)
  • Positive feedback: Output is in phase with input (0° shifted)
  • Barkhausen criteria: Positive feedback with unity gain creates oscillation

Mnemonic: “SIGN” - “Stability Increases with Gain Negation”

Question 2(a) [3 marks]
#

State and explain Barkhausen’s criteria for oscillations.

Answer: Barkhausen’s criteria define conditions for sustained oscillations in a feedback system.

Diagram:

flowchart LR
    A[Amplifier] --> B[Feedback Network]
    B --> A
    A -- "Loop Gain = 1" --> C[Sustained Oscillation]
    A -- "Loop Gain < 1" --> D[Damped Oscillation]
    A -- "Loop Gain > 1" --> E[Growing Oscillation]

  • Gain condition: Loop gain (A×β) must equal 1 (unity)
  • Phase condition: Total phase shift must be 0° or 360°
  • Practical implementation: Initial loop gain > 1, then stabilizes at 1

Mnemonic: “LOOP” - “Loop’s Overall Output Phase”

Question 2(b) [4 marks]
#

Compare Fixed bias, Collector to base bias & Voltage divider bias methods.

Answer: Different biasing techniques provide varying degrees of stability and temperature compensation.

Table:

ParameterFixed BiasCollector-Base BiasVoltage Divider Bias
StabilityPoorBetterExcellent
Circuit complexitySimpleMediumComplex
Temperature stabilityPoorMediumGood
Components1 Resistor1 Resistor3-4 Resistors
Stability factor (S)HighMediumLow
  • Fixed bias: Single resistor from base to VCC
  • Collector-base bias: Feedback resistor from collector to base
  • Voltage divider: Two resistors create stable reference voltage

Mnemonic: “STORM” - “Stability Through Optimized Resistor Methods”

Question 2(c) [7 marks]
#

Write short note on Hartley oscillator.

Answer: Hartley oscillator is an LC oscillator with a tapped inductor for feedback.

Diagram:

graph LR
    A[Amplifier] --- B[Feedback Network]
    B --- A
    subgraph "Feedback Network"
    L1[L1] --- L2[L2]
    L1 --- C1[C]
    L2 --- C1
    end

  • Circuit components: Amplifier, tapped inductor (L1+L2), capacitor C
  • Frequency formula: f = 1/[2π√(LC)] where L = L1+L2
  • Advantages: Simple design, good frequency stability
  • Drawbacks: Size of inductors, limited frequency range
  • Applications: RF signal generators, radio receivers, communication

Mnemonic: “TILC” - “Tapped Inductor with LC Circuit”

OR
#

Question 2(a) [3 marks]
#

Explain working of transistor as a switch.

Answer: Transistor switches between cutoff (OFF) and saturation (ON) regions for digital applications.

Diagram:

flowchart LR
    A[Input] --> B{Transistor}
    B -- "Saturation (ON)" --> C[Output LOW]
    B -- "Cutoff (OFF)" --> D[Output HIGH]

  • Cutoff region: VBE < 0.7V, acts as open switch, VCE ≈ VCC
  • Saturation region: VBE > 0.7V, acts as closed switch, VCE ≈ 0.2V
  • Switching time: Limited by junction capacitance

Mnemonic: “COPS” - “Cutoff-On-Produces Switching”

Question 2(b) [4 marks]
#

Define heat sink. List types of heat sink and give its applications.

Answer: Heat sink is a thermal conductor that transfers heat away from electronic components.

Diagram:

TransistorHeatSink

Types of Heat Sinks:

TypeDescriptionApplication
PassiveNo moving parts, natural convectionLow-power devices
ActiveWith fans or pumpsHigh-power amplifiers
Liquid-cooledUses fluid for heat transferComputing systems
FinnedMultiple fins increase surface areaPower transistors
  • Purpose: Prevents thermal runaway and component failure
  • Materials: Aluminum, copper, or alloys with high thermal conductivity

Mnemonic: “COOL” - “Conducting Out Of Local heat”

Question 2(c) [7 marks]
#

Explain advantages and disadvantages of negative feedback in amplifiers in detail.

Answer: Negative feedback returns a portion of output signal to input with opposite phase.

Table:

AdvantagesDisadvantages
Stabilizes gainReduces overall gain
Increases bandwidthMore components needed
Reduces distortionMore power consumption
Decreases noiseComplex circuit design
Controls input/output impedancePotential oscillation if improperly designed
Improves linearitySignal loss in feedback network

Diagram:

graph LR
    A[Input] --> B[Amplifier]
    B --> C[Output]
    C -- "Feedback Network" --> D[Subtractor]
    D --> B

  • Gain stabilization: Makes gain dependent on passive components
  • Bandwidth extension: Increases by factor equal to gain reduction
  • Feedback factor: β determines amount of improvement

Mnemonic: “STABLE” - “Stabilized Transmission And Bandwidth with Less Error”

Question 3(a) [3 marks]
#

Draw symbol of SCR and explain working of SCR.

Answer: Silicon Controlled Rectifier (SCR) is a four-layer PNPN device with three terminals.

Symbol:

G-->AKACnaotdheo)de)
  • Structure: P-N-P-N four-layer semiconductor device
  • Operation: Remains OFF until gate triggered, then conducts until current falls below holding value
  • Terminals: Anode, Cathode, Gate

Mnemonic: “AGK” - “Anode-Gate controls Kathode current”

Question 3(b) [4 marks]
#

Explain two transistor analogy of SCR with circuit diagram.

Answer: SCR can be represented as interconnected PNP and NPN transistors sharing junctions.

Diagram:

GateAnPdNePCNaPtNhode
  • PNP section: Upper transistor with collector connected to NPN base
  • NPN section: Lower transistor with collector connected to PNP base
  • Triggering: Small gate current turns on NPN, which turns on PNP
  • Regenerative action: Each transistor supplies base current to other

Mnemonic: “PNPN” - “Positive-Negative-Positive-Negative layers”

Question 3(c) [7 marks]
#

Explain the working of TRIAC based fan regulator with circuit diagram.

Answer: TRIAC-based fan regulator controls AC power through phase control.

Circuit Diagram:

AACCC1R1GZM_MTVT1_2Fan
  • Phase control: Varies firing angle of TRIAC to control power
  • Diac: Provides bidirectional triggering for TRIAC
  • RC timing circuit: R1 and C1 set phase delay
  • Variable resistor: Adjusts phase delay for speed control
  • Protection: RC snubber prevents false triggering

Mnemonic: “TRIAC” - “Triggered Response In AC Circuits”

OR
#

Question 3(a) [3 marks]
#

Draw V-I characteristics of DIAC and TRIAC.

Answer: DIACs and TRIACs are bidirectional devices with symmetrical characteristics.

DIAC Characteristics:

xychart-beta
    title "DIAC V-I Characteristics"
    x-axis [-40, -30, -20, -10, 0, 10, 20, 30, 40]
    y-axis "Current (mA)" -30 --> 30
    line [30, 5, 0, 0, 0, 0, 0, 5, 30]
    annotations
        -VBO "Breakover Voltage (-VBO)"
        VBO "Breakover Voltage (VBO)"

TRIAC Characteristics:

xychart-beta
    title "TRIAC V-I Characteristics"
    x-axis [-40, -30, -20, -10, 0, 10, 20, 30, 40]
    y-axis "Current (mA)" -40 --> 40
    line [40, 40, 40, 5, 0, 5, 40, 40, 40]
    annotations
        -VBO "Breakover (-VBO)"
        VBO "Breakover (VBO)"

  • DIAC: Bidirectional diode that conducts after breakover voltage
  • TRIAC: Three-terminal device that conducts in both directions when triggered

Mnemonic: “BIBO” - “Bidirectional In, Bidirectional Out”

Question 3(b) [4 marks]
#

Explain the Gate triggering method of SCR.

Answer: Gate triggering is the most common method to activate an SCR.

Diagram:

RCAK
  • Gate pulse: Small current applied between gate and cathode
  • Triggering methods: DC, AC, or pulse signals
  • Current requirements: Typically 5-20mA gate current
  • Advantages: Low power control of high-power circuits

Mnemonic: “GATE” - “Gain Activation Through Electron flow”

Question 3(c) [7 marks]
#

Explain SCR application for DC power control.

Answer: SCR controls DC power by chopping the supply voltage at variable duty cycles.

Circuit:

DC--GNPCDWt-Mr-l-----------S-C-R-Output
  • Phase control: Varies firing angle to control average power
  • PWM control: Pulse width modulation for efficient control
  • Applications: DC motor speed control, dimming, heating
  • Advantages: High efficiency, no moving parts, reliable
  • Limitations: Unidirectional current flow, needs commutation

Mnemonic: “POWER” - “Pulse Operation With Electronic Regulation”

Question 4(a) [3 marks]
#

List characteristics of Ideal OP-AMP.

Answer: Ideal operational amplifiers have perfect characteristics that real devices approximate.

Table:

CharacteristicIdeal Value
Open loop gainInfinite
Input impedanceInfinite
Output impedanceZero
BandwidthInfinite
CMRRInfinite
Slew rateInfinite
Offset voltageZero
  • Practical values: Actual op-amps have limitations
  • Implications: Circuit design must account for real limitations

Mnemonic: “IBOCSS” - “Infinite Bandwidth, Open-loop gain, CMRR, Slew rate, and Sensitivity”

Question 4(b) [4 marks]
#

Explain working of differential amplifier using OP-AMP with circuit diagram.

Answer: Differential amplifier amplifies the voltage difference between two inputs.

Circuit:

VV12RR11RR22Vout
  • Gain formula: Vout = (V1-V2) × (R2/R1)
  • Common mode rejection: Suppresses signals common to both inputs
  • Applications: Instrumentation, medical equipment, audio

Mnemonic: “DIFF” - “Dual Input For Feedback”

Question 4(c) [7 marks]
#

Explain OP-AMP as an inverting amplifier (Closed loop) and derive the formula of voltage gain.

Answer: Inverting amplifier produces output that is inverted and amplified version of input.

Circuit:

VinGNDRiRfVout

Gain Derivation:

  • Apply KCL at inverting input: I₁ + I₂ = 0

  • I₁ = (Vin - V⁻)/Ri and I₂ = (Vout - V⁻)/Rf

  • At virtual ground, V⁻ ≈ 0

  • Therefore: Vin/Ri + Vout/Rf = 0

  • Solving for Vout/Vin: Av = -Rf/Ri

  • Characteristics: Output 180° out of phase with input

  • Feedback: Creates virtual ground at inverting input

  • Closed loop gain: Controlled by external resistors

Mnemonic: “VAIN” - “Virtual ground Amplification Inverts Negative”

OR
#

Question 4(a) [3 marks]
#

Define the following parameters of OPAMP: 1) CMRR
2) Slew rate
3) Gain Bandwidth Product

Answer: These parameters define key performance characteristics of operational amplifiers.

Table:

ParameterDefinitionImportance
CMRRRatio of differential gain to common-mode gainHigher is better for rejecting noise
Slew RateMaximum rate of output voltage change (V/μs)Determines large-signal bandwidth
Gain-Bandwidth ProductProduct of gain and frequency (MHz)Measures high-frequency performance
  • CMRR: Typically 80-120dB in quality op-amps
  • Slew Rate: Limits output for high-frequency, high-amplitude signals
  • GBP: Remains constant as frequency increases

Mnemonic: “CSG” - “Common-mode rejection, Speed, and Gain”

Question 4(b) [4 marks]
#

Draw and explain summing amplifier using OP-AMP.

Answer: Summing amplifier produces output proportional to weighted sum of input voltages.

Circuit:

VVV123RRR123RfVout
  • Output formula: Vout = -Rf(V₁/R₁ + V₂/R₂ + V₃/R₃)
  • Applications: Audio mixer, analog computers, signal processing
  • Advantage: Multiple inputs can be processed simultaneously

Mnemonic: “SUM” - “Several Unified Multipliers”

Question 4(c) [7 marks]
#

Draw the pin diagram of IC 555 and explain Monostable multivibrator using IC555 with waveform.

Answer: IC 555 timer in monostable mode produces a single pulse of fixed duration when triggered.

Pin Diagram:

1234::::1234GTORNrueDitsgpe5gut5et5r5:678:::8765CoTDVnhiCtrsCrecoshlhaorlgde

Circuit and Waveform:

graph TB
    subgraph "Monostable Circuit"
    VCC --- R1 --- A
    A --- C1 --- GND
    A --- Pin6 & Pin7
    Pin2 --- Trigger
    Pin3 --- Output
    Pin4 --- Reset
    Pin8 --- VCC
    Pin1 --- GND
    end
    
    subgraph "Waveforms"
    direction TB
    Trig[Trigger] --> O1[Output]
    end

  • Operation: Negative trigger starts timing cycle
  • Time period: T = 1.1 × R × C
  • Applications: Timers, pulse generation, debouncing
  • Advantages: Simple, reliable, widely available

Mnemonic: “TIMER” - “Triggered Input Makes Extended Response”

Question 5(a) [3 marks]
#

Draw block diagram of SMPS and give its applications.

Answer: Switch Mode Power Supply (SMPS) uses switching elements for efficient power conversion.

Block Diagram:

flowchart LR
    A[AC Input] --> B[EMI Filter]
    B --> C[Rectifier]
    C --> D[Filter]
    D --> E[Switching Circuit]
    E --> F[Transformer]
    F --> G[Output Rectifier]
    G --> H[Output Filter]
    H --> I[Output]
    J[Feedback Control] --> E
    I --> J

Applications:

  • Computer power supplies

  • Mobile phone chargers

  • TV power supplies

  • Industrial power systems

  • LED lighting drivers

  • Advantages: High efficiency, small size, lightweight

  • Types: Buck, boost, buck-boost, flyback converters

Mnemonic: “SAFE” - “Switching Achieves Filtered Energy”

Question 5(b) [4 marks]
#

Explain working of Regulated Power Supply with diagram.

Answer: Regulated power supply maintains constant output despite input or load variations.

Block Diagram:

flowchart LR
    A[AC Input] --> B[Transformer]
    B --> C[Rectifier]
    C --> D[Filter]
    D --> E[Regulator]
    E --> F[Output]
    G[Feedback] --> E
    F --> G

  • Transformer: Steps down AC voltage to required level
  • Rectifier: Converts AC to pulsating DC (diode bridge)
  • Filter: Smooths DC with capacitors
  • Regulator: Maintains constant output voltage
  • Feedback: Compensates for input/load variations

Mnemonic: “TRFRO” - “Transform, Rectify, Filter, Regulate, Output”

Question 5(c) [7 marks]
#

Explain basic block diagram of OP-AMP with diagram.

Answer: Operational amplifier’s internal structure consists of several stages performing specific functions.

Block Diagram:

flowchart LR
    A[Differential Input Stage] --> B[Intermediate Stage]
    B --> C[Level Shifter]
    C --> D[Output Stage]
    E[Bias Circuit] --> A & B & C & D

  • Differential input stage: High impedance, amplifies difference
  • Intermediate stage: Provides additional gain
  • Level shifter: Adjusts DC level between stages
  • Output stage: Low impedance, current amplification
  • Bias circuit: Establishes operating points for all stages
  • Compensation: Internal capacitor for stability

Mnemonic: “DILO” - “Differential Input, Level shift, Output”

OR
#

Question 5(a) [3 marks]
#

Explain adjustable voltage regulator using LM317 with diagram.

Answer: LM317 is a versatile adjustable positive voltage regulator with output range of 1.25V to 37V.

Circuit:

ViCGn1NDAdGV3jRRNLi112DMn7O3u1t7GCN2DGNDVout
  • Formula: Vout = 1.25(1 + R2/R1)
  • Advantages: Simple adjustment, built-in protection
  • Applications: Variable power supplies, battery chargers

Mnemonic: “AVR” - “Adjustable Voltage Regulation”

Question 5(b) [4 marks]
#

Give the difference between Fixed voltage regulator IC and Variable voltage regulator IC.

Answer: Voltage regulator ICs differ in their configurability and application requirements.

Table:

ParameterFixed Voltage RegulatorVariable Voltage Regulator
Output voltagePredetermined (e.g., 5V, 12V)Adjustable over a range
External componentsMinimal (capacitors only)Requires resistors for setting
Series78xx (positive), 79xx (negative)LM317 (positive), LM337 (negative)
ApplicationsStandard equipmentCustom designs, laboratory supplies
FlexibilityLimited to fixed valuesHighly adaptable
Pin countTypically 3 pins3 or more pins
  • Fixed regulators: Simple to use, limited adjustment
  • Variable regulators: More versatile, require calculation

Mnemonic: “FOCUS” - “Fixed Output Compared to User-Set”

Question 5(c) [7 marks]
#

List applications of OP-AMP. Explain working operation of D to A converter with circuit diagram using OP-AMP.

Answer: Op-amps have numerous applications; D/A converters transform digital signals to analog.

Applications of OP-AMP:

  • Amplifiers (inverting, non-inverting)
  • Filters (active filters)
  • Oscillators
  • Comparators
  • Integrators and differentiators
  • Voltage followers
  • Instrumentation circuits

R-2R Ladder DAC Circuit:

2DR3SRWD22SRRW|GD2RN1SRRfDW|D20SRRW|GNDVout
  • Working principle: Digital inputs weight currents through resistor network
  • Resistance values: Binary-weighted or R-2R ladder network
  • Conversion: Output voltage proportional to digital input value
  • Resolution: Determined by number of bits (2ⁿ levels)

Mnemonic: “DART” - “Digital to Analog Resistor Translation”

Related

Electronics Devices & Circuits (1323202) - Winter 2024 Solution
14 mins
Study-Material Solutions Electronics 1323202 2024 Winter
Elements of Electrical & Electronics Engineering (1313202) - Winter 2023 Solution
15 mins
Study-Material Solutions Electrical Electronics 1313202 2023 Winter
Electronics Devices & Circuits (1323202) - Summer 2023 Solution
13 mins
Study-Material Solutions Electronics 1323202 2023 Summer
Fundamentals of Electronics (4311102) - Winter 2023 Solution
19 mins
Study-Material Solutions Electronics 4311102 2023 Winter
Electronic Circuits & Applications (4321103) - Winter 2023 Solution
16 mins
Study-Material Solutions Electronics 4321103 2023 Winter
Antenna & Wave Propagation (4341106) - Winter 2023 Solution
14 mins
Study-Material Solutions Antenna Wave-Propagation 4341106 2023 Winter