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Digital & Data Communication (4343201) - Winter 2024 Solution

25 mins· ·
Study-Material Solutions Digital-Communication 4343201 2024 Winter
Milav Dabgar
Author
Milav Dabgar
Experienced lecturer in the electrical and electronic manufacturing industry. Skilled in Embedded Systems, Image Processing, Data Science, MATLAB, Python, STM32. Strong education professional with a Master’s degree in Communication Systems Engineering from L.D. College of Engineering - Ahmedabad.
Table of Contents

Question 1(a) [3 marks]
#

Differentiate Basic modes of Communication: Broad casting communication and Point to Point Communication.

Answer:

ParameterBroadcasting CommunicationPoint to Point Communication
DefinitionOne transmitter sends signals to multiple receivers simultaneouslyOne transmitter communicates with one specific receiver
DirectionUnidirectional (one-way)Bidirectional (two-way)
ExamplesTV, Radio, FMTelephone, Mobile calls, Private networks
PrivacyLow (signal available to everyone in range)High (dedicated connection between endpoints)
EfficiencyHigh for mass communicationBetter for personal/private communication

Mnemonic: “BDPEC” - Broadcasting Distributes to Public, Endpoints Connect in point-to-point

Question 1(b) [4 marks]
#

Define: Bit Rate, Baud Rate, Bandwidth and Repeater Distance.

Answer:

TermDefinition
Bit RateNumber of binary bits transmitted per second (bps). Measures actual data transfer speed.
Baud RateNumber of signal units or symbols transmitted per second. One symbol may contain multiple bits.
BandwidthRange of frequencies used by a signal, measured in Hertz (Hz). Determines maximum data capacity of a channel.
Repeater DistanceMaximum distance between repeaters in a communication system before signal degradation requires regeneration.

Diagram:

graph LR
    A[Signal] --> B[Bandwidth = Max Frequency - Min Frequency]
    C[Bits] --> D[Bit Rate = Bits/Second]
    E[Symbols] --> F[Baud Rate = Symbols/Second]
    G[Distance] --> H[Repeater Distance = Max Distance Before Signal Regeneration]

Mnemonic: “BBRR” - “Better Bandwidth Requires Repeaters”

Question 1(c) [7 marks]
#

Draw the block diagram of digital communication system. Explain the functions of each block in brief. State advantages and disadvantages of it.

Answer:

Block Diagram:

graph LR
    A[Input Source] --> B[Source Encoder]
    B --> C[Channel Encoder]
    C --> D[Digital Modulator]
    D --> E[Channel]
    E --> F[Digital Demodulator]
    F --> G[Channel Decoder]
    G --> H[Source Decoder]
    H --> I[Output]

Functions:

BlockFunction
Source EncoderConverts analog signal to digital, removes redundancy, compresses data
Channel EncoderAdds redundancy for error detection and correction
Digital ModulatorConverts digital data to suitable form for transmission (ASK, FSK, PSK, etc.)
ChannelMedium through which signal travels (wired/wireless)
Digital DemodulatorExtracts original digital data from received modulated signal
Channel DecoderDetects and corrects errors using added redundancy
Source DecoderDecompresses data and converts to original form

Advantages and Disadvantages:

AdvantagesDisadvantages
Better noise immunityRequires more bandwidth
Easier signal regenerationComplex implementation
Secure transmission possibleSynchronization required
Integration with computersQuantization errors
Better quality for long distanceHigher cost for simple applications

Mnemonic: “SECDCSO” - “Secure Encoding Creates Digital Communication System Output”

Question 1(c) OR [7 marks]
#

Justify the needs of multiplexing techniques for digital communication. Draw and explain Time Division multiplexing technique in brief. Discuss its merits and demerits.

Answer:

Need for Multiplexing:

NeedExplanation
Channel EfficiencyAllows multiple signals on one channel, saving bandwidth
Cost ReductionReduces need for multiple transmission media
Infrastructure UtilizationMaximizes use of expensive infrastructure
Spectrum ConservationConserves limited frequency spectrum

Time Division Multiplexing (TDM):

graph LR
    A1[Input 1] --> M[Multiplexer]
    A2[Input 2] --> M
    A3[Input 3] --> M
    A4[Input 4] --> M
    M --> T[Transmission Channel]
    T --> D[Demultiplexer]
    D --> B1[Output 1]
    D --> B2[Output 2]
    D --> B3[Output 3]
    D --> B4[Output 4]

Working: In TDM, each input signal gets a specific time slot. The multiplexer samples each input sequentially, combining them into a single high-speed data stream. At the receiver, the demultiplexer separates the stream back into original signals based on timing.

Merits and Demerits:

MeritsDemerits
Efficient bandwidth usageRequires synchronization
No guard bands neededComplex buffering required
No cross-talkTiming issues can cause errors
Flexible allocationUnused slots waste capacity
Digital implementationHigher data rate than individual channels

Mnemonic: “TIME” - “Transmission Interleaves Multiple Endpoints”

Question 2(a) [3 marks]
#

Differentiate: Coherent and Non-Coherent Detection Technique.

Answer:

ParameterCoherent DetectionNon-Coherent Detection
Phase InformationUses phase informationIgnores phase information
Local OscillatorRequiredNot required
ComplexityMore complexSimpler
PerformanceBetter noise immunityLess efficient in noise
ImplementationDifficultEasier
ApplicationsHigh-quality systemsLow-cost systems

Mnemonic: “PLCPIA” - “Phase Local Complex Performance Implementation Applications”

Question 2(b) [4 marks]
#

Sketch the ASK, FSK, PSK and QPSK waveform for the data sequence 101100110110.

Answer:

IDAFFPPQ9120naSSSSSP087°ptKKKKKS°00ua:K°°0t:HL01:01io°8011:Dgw:0:01ah:°::t::a__:1___01_1__0_0_1_1__0_11____0

Mnemonic: “AFPQ” - “Amplitude Frequency Phase Quadrature”

Question 2(c) [7 marks]
#

Explain the principle of 16-QAM. Also explain constellation diagram and waveform for 16-QAM. Write its advantages and disadvantages.

Answer:

Principle of 16-QAM: 16-QAM (Quadrature Amplitude Modulation) combines amplitude and phase modulation to transmit 4 bits per symbol. It uses 16 different combinations of amplitude and phase, allowing higher data rates in the same bandwidth.

Constellation Diagram:

EachpointQrepresents4bIits(0000to1111)

Waveform: The 16-QAM waveform varies in both amplitude (4 levels) and phase (4 phases), creating 16 unique symbols.

Advantages and Disadvantages:

AdvantagesDisadvantages
High spectral efficiencySensitive to noise and interference
Higher data rateRequires higher SNR
Bandwidth efficientComplex implementation
Better use of channel capacitySusceptible to amplitude distortion

Mnemonic: “SCHAP” - “Sixteen Combinations Have Amplitude and Phase”

Question 2(a) OR [3 marks]
#

Compare: ASK and PSK

Answer:

ParameterASK (Amplitude Shift Keying)PSK (Phase Shift Keying)
Modulation ParameterAmplitudePhase
Noise ImmunityPoorGood
Power EfficiencyLess efficientMore efficient
Bandwidth EfficiencyLowerHigher
ImplementationSimpleMore complex
BER PerformanceHigher error rateLower error rate

Mnemonic: “ANPBIP” - “Amplitude Noise Power Bandwidth Implementation Performance”

Question 2(b) OR [4 marks]
#

Draw the block diagram of BPSK modulator and demodulator.

Answer:

BPSK Modulator:

graph LR
    A[Binary Input] --> B[NRZ Encoder]
    B --> C[Multiplier]
    D[Carrier Generator] --> C
    C --> E[BPSK Output]

BPSK Demodulator:

graph LR
    A[BPSK Input] --> B[Multiplier]
    C[Local Oscillator] --> D[Phase Synchronizer]
    D --> B
    B --> E[Low Pass Filter]
    E --> F[Decision Device]
    F --> G[Binary Output]

Mnemonic: “MNECO” - “Modulation Needs Encoding, Carriers, Oscillators”

Question 2(c) OR [7 marks]
#

Explain QPSK generation and detection with the help of block diagram and waveform. Discuss its advantages and disadvantages.

Answer:

QPSK Generation Block Diagram:

graph LR
    A[Binary Input] --> B[Serial to Parallel]
    B -->|I-channel| C[Multiplier I]
    B -->|Q-channel| D[Multiplier Q]
    E[Carrier Generator] --> C
    E --> F[90° Phase Shifter]
    F --> D
    C --> G[Adder]
    D --> G
    G --> H[QPSK Output]

QPSK Detection Block Diagram:

graph LR
    A[QPSK Input] --> B[Multiplier I]
    A --> C[Multiplier Q]
    D[Local Oscillator] --> B
    D --> E[90° Phase Shifter]
    E --> C
    B --> F[LPF I]
    C --> G[LPF Q]
    F --> H[Decision Device I]
    G --> I[Decision Device Q]
    H --> J[Parallel to Serial]
    I --> J
    J --> K[Binary Output]

QPSK Waveform: Each symbol in QPSK represents 2 bits, with 4 possible phase states (0°, 90°, 180°, 270°).

Advantages and Disadvantages:

AdvantagesDisadvantages
Twice the data rate of BPSKMore complex implementation
Same bandwidth as BPSKSensitive to phase errors
Good noise immunityRequires carrier recovery
Spectral efficiencyMore complex synchronization

Mnemonic: “PACE” - “Phase Alteration Carries Extra data”

Question 3(a) [3 marks]
#

State the features of RS-422.

Answer:

Features of RS-422
Differential signaling for noise immunity
Maximum data rate of 10 Mbps
Maximum cable length of 1200 meters
Multi-drop capability (1 driver, up to 10 receivers)
Balanced transmission line
Higher noise immunity than RS-232

Mnemonic: “DMMBHN” - “Differential Maximum Multi-drop Balanced Higher Noise-immunity”

Question 3(b) [4 marks]
#

Define: Entropy, Information, Mutual Information and Probability.

Answer:

TermDefinition
EntropyMeasure of uncertainty or randomness in a message source, calculated as H(X) = -∑p(x)log₂p(x)
InformationReduction in uncertainty when a message is received, measured in bits
Mutual InformationMeasure of dependency between two random variables, indicating how much information one variable contains about the other
ProbabilityMathematical measure of likelihood that an event will occur, ranging from 0 (impossible) to 1 (certain)

Diagram:

graph TD
    A[Entropy of X: H(X)] --- C[Mutual Information: I(X;Y)]
    B[Entropy of Y: H(Y)] --- C
    C --- D[Measures shared information between X and Y]

Mnemonic: “EIMP” - “Entropy Information Measures Probability”

Question 3(c) [7 marks]
#

Explain Huffman Code and Shannon-Fano code with suitable example.

Answer:

Huffman Code: Huffman coding assigns variable-length codes to symbols based on their frequencies, with shorter codes for more frequent symbols.

Example:

SymbolFrequencyHuffman Code
A45%0
B25%10
C15%110
D10%1110
E5%1111

Huffman Tree:

graph TD
    A[100%] --> B[60%]
    A --> C[A: 40%/0]
    B --> D[30%]
    B --> E[B: 30%/10]
    D --> F[15%]
    D --> G[C: 15%/110]
    F --> H[D: 10%/1110]
    F --> I[E: 5%/1111]

Shannon-Fano Code: Shannon-Fano algorithm recursively divides symbols into two groups of similar frequency, then assigns 0 to one group and 1 to the other.

Example:

SymbolFrequencyShannon-Fano Code
A45%0
B25%10
C15%110
D10%1110
E5%1111

Shannon-Fano Tree:

graph TD
    A[A,B,C,D,E] --> B[A/0]
    A --> C[B,C,D,E]
    C --> D[B/10]
    C --> E[C,D,E]
    E --> F[C/110]
    E --> G[D,E]
    G --> H[D/1110]
    G --> I[E/1111]

Mnemonic: “FREDS” - “Frequency Reduces Encoding Digit Size”

Question 3(a) OR [3 marks]
#

State the features of RS-232.

Answer:

Features of RS-232
Single-ended signaling
Maximum data rate of 20 kbps
Maximum cable length of 15 meters
Point-to-point communication (1 driver, 1 receiver)
Voltage levels: -15V to +15V
25-pin or 9-pin DB connector standard

Mnemonic: “SMPVD” - “Single Maximum Point-to-point Voltage DB-connector”

Question 3(b) OR [4 marks]
#

What is channel capacity in terms of SNR? Explain its importance.

Answer:

Channel Capacity: The maximum rate at which information can be transmitted over a communication channel with an arbitrarily small probability of error.

Formula: C = B × log₂(1 + SNR)

Where:

  • C = Channel capacity in bits per second
  • B = Bandwidth in Hertz
  • SNR = Signal-to-Noise Ratio

Importance:

Importance of Channel Capacity
Sets theoretical limits for data transmission
Guides system design and optimization
Helps evaluate performance of communication systems
Determines required bandwidth for a given data rate
Informs coding techniques to approach capacity

Diagram:

graph LR
    A[Bandwidth] --> C[Channel Capacity]
    B[SNR] --> C
    C --> D[Maximum Achievable Data Rate]

Mnemonic: “BSNR” - “Bandwidth and SNR Need Relationship”

Question 3(c) OR [7 marks]
#

Explain in detail any one error detection and error correction technique in digital communication.

Answer:

Hamming Code Error Detection and Correction

Hamming code is a linear error-correcting code that can detect and correct single-bit errors in data transmission.

Working Principle:

  1. Data bits are positioned at locations that are powers of 2 (1, 2, 4, 8, etc.)
  2. Parity bits are added at positions 1, 2, 4, 8, etc.
  3. Each parity bit checks specific data bits according to its position
  4. On receiving, parity checks identify error position

Example: 7-bit Hamming code (4 data bits, 3 parity bits)

Position1234567
Bit typeP₁P₂D₁P₄D₂D₃D₄

Parity Bit Calculation:

  • P₁ checks bits 1, 3, 5, 7 (positions 1, 3, 5, 7)
  • P₂ checks bits 2, 3, 6, 7 (positions 2, 3, 6, 7)
  • P₄ checks bits 4, 5, 6, 7 (positions 4, 5, 6, 7)

Error Correction: If an error occurs, the parity checks will indicate the error position, which can then be flipped to correct the error.

Table: Error Position from Parity Check Results

P₄P₂P₁Error Position
000No error
001Position 1
010Position 2
011Position 3
100Position 4
101Position 5
110Position 6
111Position 7

Mnemonic: “PECD” - “Parity Enables Correction of Data”

Question 4(a) [3 marks]
#

Draw the block diagram of satellite communication and explain in brief.

Answer:

Satellite Communication Block Diagram:

graph TD
    A[Ground Station 1] -->|Uplink| B[Satellite]
    B -->|Downlink| C[Ground Station 2]
    D[Transmitter] --> A
    C --> E[Receiver]

Brief Explanation: Satellite communication involves transmitting signals from an Earth station to a satellite (uplink), which then amplifies and retransmits the signals back to Earth (downlink). The satellite acts as a repeater in space, enabling long-distance communication.

Key Components:

  • Earth Stations: Transmit and receive signals
  • Transponders: Receive, amplify, and retransmit signals
  • Antennas: Transmit and receive electromagnetic waves
  • Modems: Convert digital data to analog signals and vice versa

Mnemonic: “STAR” - “Satellite Transmits And Receives”

Question 4(b) [4 marks]
#

Sketch the Unipolar NRZ, Polar RZ, Polar NRZ and AMI waveform for 10101101 data sequence.

Answer:

IDUNPRPNAnanRoZoRMptiZl:lZIuap:aa::t:orrlDaarta:10101101

Mnemonic: “UPPA” - “Unipolar Polar Polar AMI”

Question 4(c) [7 marks]
#

Explain data transmission techniques in details with suitable example for digital communication.

Answer:

Data Transmission Techniques:

TechniqueDescriptionExample
Serial TransmissionData bits sent one after another over a single channelUSB, UART communication
Parallel TransmissionMultiple bits sent simultaneously over multiple channelsPrinter ports, SCSI
Synchronous TransmissionData sent in continuous stream with timing signalsEthernet, HDLC
Asynchronous TransmissionData sent with start/stop bits as timing referencesRS-232, UART
SimplexOne-way communicationTV broadcasting
Half-DuplexTwo-way communication, one direction at a timeWalkie-talkie
Full-DuplexTwo-way simultaneous communicationTelephone calls

Serial Transmission Example:

UART:Stbairtt10101101biSttop

Parallel Transmission Example:

DCaltoac:k:1BBBBBBBB0iiiiiiii1tttttttt01765432101::::::::01

Mnemonic: “SPASH” - “Serial Parallel Asynchronous Synchronous Half-duplex”

Question 4(a) OR [3 marks]
#

Interpret the aspects of spread spectrum techniques.

Answer:

Spread Spectrum Techniques:

AspectInterpretation
Bandwidth SpreadingSignal spread over a wider bandwidth than required
SecurityDifficult to intercept or jam due to spreading
Noise ImmunityResistant to narrowband interference
Multiple AccessAllows multiple users to share same frequency band
Low Power DensitySignal power spread across wide band, appearing as noise

Diagram:

graph LR
    A[Narrow Band Signal] --> B[Spreading]
    B --> C[Wideband Spread Signal]
    D[Spreading Code] --> B

Mnemonic: “BSNML” - “Bandwidth Security Noise Multiple Low-power”

Question 4(b) OR [4 marks]
#

Write a short note on probability and discuss its properties for digital communication.

Answer:

Probability in Digital Communication: Probability theory provides the mathematical foundation for analyzing performance, error rates, and reliability of digital communication systems.

Properties of Probability:

PropertyDescriptionRelevance in Digital Communication
Range0 ≤ P(E) ≤ 1Sets bounds for error probability
CertaintyP(S) = 1 for sample space STotal probability of all possible outcomes
AdditivityP(A∪B) = P(A) + P(B) for disjoint eventsCalculating overall system error rates
Conditional ProbabilityP(A|B) = P(A∩B)/P(B)Useful for channel modeling
IndependenceP(A∩B) = P(A)×P(B)Analyzing uncorrelated noise sources

Applications in Digital Communication:

  • Bit Error Rate calculation
  • Signal detection theory
  • Channel capacity estimation
  • Coding efficiency analysis

Mnemonic: “RACIC” - “Range Additivity Certainty Independence Conditional”

Question 4(c) OR [7 marks]
#

Explain Data transmission mode in details with example.

Answer:

Data Transmission Modes:

ModeDescriptionDiagramExample
SimplexOne-way communication only. Transmitter can only send, receiver can only receive.
graph LR; A[Transmitter] -->|One-way| B[Receiver]
TV broadcasting, Radio
Half-DuplexTwo-way communication, but only one direction at a time.
graph LR; A[Device A] -->|Time 1| B[Device B]; B -->|Time 2| A
Walkie-talkie, CB radio
Full-DuplexTwo-way simultaneous communication.
graph LR; A[Device A] -->|Channel 1| B[Device B]; B -->|Channel 2| A
Telephone, Mobile calls

Example of Half-Duplex Communication:

DeviceAACKNRSOEEWQNLUDEEIDSNGTGMEDDNAATTTAA(ACK)DeviceB

Example of Full-Duplex Communication:

DeviceACOSSNEETNNIDDNIIUNNOGGUSDDAADTTAAATADeviceB

Mnemonic: “SHF” - “Simplex Half Full” or “Stop, Halt, Flow”

Question 5(a) [3 marks]
#

Explain Edge Computing in detail.

Answer:

Edge Computing: Edge computing is a distributed computing paradigm that brings computation and data storage closer to the location where it is needed to improve response times and save bandwidth.

Key Aspects:

AspectDescription
DecentralizationProcessing at network edge instead of central cloud
Reduced LatencyFaster response due to proximity to data source
Bandwidth EfficiencyLess data sent to cloud, reducing network congestion
Local Data ProcessingData processed near collection point
Improved SecuritySensitive data remains local, reducing exposure
ReliabilityContinues to function during cloud connectivity issues

Diagram:

graph LR
    A[IoT Devices] --> B[Edge Computing]
    B --> C[Local Processing]
    B --> D[Local Storage]
    B --> E[Cloud]
    E --> F[Central Storage & Processing]

Mnemonic: “DRBLES” - “Decentralized Reduces Bandwidth, Latency, Exposure, Strengthens reliability”

Question 5(b) [4 marks]
#

Enlist the features of 5G Technology in data communication.

Answer:

Features of 5G Technology
High Data Rates (up to 20 Gbps peak)
Ultra-Low Latency (1 ms or less)
Massive Device Connectivity (1 million devices per km²)
Network Slicing (customized virtual networks)
Beamforming (directed signal transmission)
Millimeter Wave Spectrum (24-100 GHz)
Enhanced Mobile Broadband (eMBB)
Ultra-Reliable Low-Latency Communication (URLLC)

Diagram:

graph TD
    A[5G Technology] --> B[High Data Rates]
    A --> C[Ultra-Low Latency]
    A --> D[Massive Connectivity]
    A --> E[Network Slicing]
    A --> F[Three Main Use Cases]
    F --> G[eMBB]
    F --> H[URLLC]
    F --> I[mMTC]

Mnemonic: “HUMBLE-MN” - “High-speed Ultra-low-latency Massive Beamforming Low-latency Enhanced Millimeter Network”

Question 5(c) [7 marks]
#

Write a details note on Data communication including its characteristics and components.

Answer:

Data Communication: Data communication is the process of transferring digital information between two or more points.

Characteristics of Data Communication:

CharacteristicDescription
DeliverySystem must deliver data to correct destination
AccuracySystem must deliver data accurately, without errors
TimelinessSystem must deliver data in a timely manner
JitterSystem must maintain consistent timing between data arrivals
SecuritySystem must protect data from unauthorized access

Components of Data Communication:

ComponentDescription
MessageThe information (data) to be communicated
SenderDevice that sends the data message
ReceiverDevice that receives the message
Transmission MediumPhysical path by which message travels
ProtocolSet of rules governing data communication

Data Communication Model:

graph LR
    A[Sender] --> B[Encoder]
    B --> C[Transmission Medium]
    C --> D[Decoder]
    D --> E[Receiver]
    F[Protocol] --> A
    F --> B
    F --> C
    F --> D
    F --> E

Data Communication Types:

TypeDescription
AnalogContinuous signal that varies in amplitude or frequency
DigitalDiscrete signal represented by binary digits (0s and 1s)
ParallelMultiple bits transmitted simultaneously on separate channels
SerialBits transmitted sequentially on a single channel

Mnemonic: “DATJS-MSRTP” - “Delivery Accuracy Timeliness Jitter Security - Message Sender Receiver Transmission Protocol”

Question 5(a) OR [3 marks]
#

Identify and write privacy consideration in Data communication.

Answer:

Privacy Considerations in Data Communication:

Privacy ConsiderationDescription
Data EncryptionProtecting data during transmission using encryption algorithms
Access ControlEnsuring only authorized users can access communication systems
AuthenticationVerifying the identity of users and devices
Data MinimizationCollecting only necessary data to minimize privacy risks
Secure ProtocolsUsing communication protocols with built-in security features
End-to-End SecurityEnsuring data is protected throughout the entire communication path

Diagram:

graph TD
    A[Privacy in Data Communication] --> B[Data Encryption]
    A --> C[Access Control]
    A --> D[Authentication]
    A --> E[Data Minimization]
    A --> F[Secure Protocols]
    A --> G[End-to-End Security]

Mnemonic: “DAAESE” - “Data is Authenticated, Accessed, Encrypted Securely End-to-end”

Question 5(b) OR [4 marks]
#

What is block chain in communication security? Enlist its features.

Answer:

Blockchain in Communication Security: Blockchain is a distributed ledger technology that provides secure, tamper-proof record-keeping for data communication through cryptographic linking of data blocks.

Features of Blockchain:

FeatureDescription
DecentralizationNo central authority; distributed across network nodes
ImmutabilityOnce recorded, data cannot be altered without consensus
TransparencyAll transactions visible to authorized participants
Cryptographic SecurityData secured using advanced cryptographic techniques
Consensus MechanismNetwork agrees on validity of transactions
Smart ContractsSelf-executing contracts with terms directly written in code
Distributed StorageData stored across multiple nodes, preventing single point of failure

Diagram:

graph LR
    A[Block 1] -->|Hash Link| B[Block 2]
    B -->|Hash Link| C[Block 3]
    C -->|Hash Link| D[Block 4]

    A --> A1[Transactions]
    A --> A2[Hash]
    A --> A3[Previous Hash]
    
    B --> B1[Transactions]
    B --> B2[Hash]
    B --> B3[Previous Hash]

Mnemonic: “DITCSD” - “Decentralized Immutable Transparent Cryptographic Secure Distributed”

Question 5(c) OR [7 marks]
#

Write and illustrate different communication ports: USB, HDMI, RCA and Ethernet.

Answer:

Communication Ports:

  1. USB (Universal Serial Bus):
UUSSBB--AC

Features:

  • Data transfer, power delivery, and device connection
  • Versions: USB 1.0 to USB 4.0
  • Speed: Up to 40 Gbps (USB4)
  • Hot-swappable
  • Supports up to 127 devices in cascade
  1. HDMI (High-Definition Multimedia Interface):
HDMI

Features:

  • Digital audio/video transmission
  • Versions: HDMI 1.0 to HDMI 2.1
  • Resolution support: Up to 10K
  • Bandwidth: Up to 48 Gbps (HDMI 2.1)
  • HDCP (High-bandwidth Digital Content Protection)
  • CEC (Consumer Electronics Control) for device control
  1. RCA (Radio Corporation of America):
RWVehiRdWidteeoGRAreuGeRddeinoBlBue

Features:

  • Analog audio/video transmission
  • Color-coded connectors (Red, White, Yellow)
  • Used for composite video and stereo audio
  • Simple connection but limited quality
  • No digital content protection
  • Being phased out by digital standards
  1. Ethernet (RJ-45):
||R|J|-|4|5|||

Features:

  • Network connectivity
  • Standards: 10BASE-T to 10GBASE-T
  • Speed: 10 Mbps to 10 Gbps
  • Uses twisted-pair cabling (Cat5e, Cat6, Cat6a)
  • Supports Power over Ethernet (PoE)
  • Base communication for TCP/IP networks
  • Maximum cable length: 100 meters

Comparison Table:

PortTypeData TypeMax SpeedPower DeliveryMax Length
USBDigitalData/Power40 GbpsYes (100W)5m
HDMIDigitalAudio/Video48 GbpsLimited15m
RCAAnalogAudio/VideoLowNo10m
EthernetDigitalNetwork Data10 GbpsYes (PoE)100m

Mnemonic: “UHRE” - “USB Handles Rapid Ethernet, HDMI Delivers Rich Entertainment”

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